Python: tree data structure
# 树结构
from pythonds.basic.stack import Stack #pip install pythonds
from pythonds.trees.binaryTree import BinaryTree
from collections import defaultdict
import json #JSON-esque
def tree():
return defaultdict(tree) def dicts(t):
return {k: dicts(t[k]) for k in t} #迭代
def add(t, keys):
for key in keys: t = t[key] users = tree();
users['harold']['username'] = 'hrldcpr'
users['handler']['username'] = 'matthandlersux'; print(json.dumps(users)); taxonomy = tree();
taxonomy['Animalia']['Chordata']['Mammalia']['Carnivora']['Felidae']['Felis']['cat']
taxonomy['Animalia']['Chordata']['Mammalia']['Carnivora']['Felidae']['Panthera']['lion']
taxonomy['Animalia']['Chordata']['Mammalia']['Carnivora']['Canidae']['Canis']['dog']
taxonomy['Animalia']['Chordata']['Mammalia']['Carnivora']['Canidae']['Canis']['coyote']
taxonomy['Plantae']['Solanales']['Solanaceae']['Solanum']['tomato']
taxonomy['Plantae']['Solanales']['Solanaceae']['Solanum']['potato']
taxonomy['Plantae']['Solanales']['Convolvulaceae']['Ipomoea']['sweet potato'] print(dicts(taxonomy)); dtstr=add(taxonomy,'Animalia,Chordata,Mammalia,Cetacea,Balaenopteridae,Balaenoptera,blue whale'.split(',')) def buildParseTree(fpexp):
fplist = fpexp.split()
pStack = Stack()
eTree = BinaryTree('')
pStack.push(eTree)
currentTree = eTree
for i in fplist:
if i == '(':
currentTree.insertLeft('')
pStack.push(currentTree)
currentTree = currentTree.getLeftChild()
elif i not in ['+', '-', '*', '/', ')']:
currentTree.setRootVal(int(i))
parent = pStack.pop()
currentTree = parent
elif i in ['+', '-', '*', '/']:
currentTree.setRootVal(i)
currentTree.insertRight('')
pStack.push(currentTree)
currentTree = currentTree.getRightChild()
elif i == ')':
currentTree = pStack.pop()
else:
raise ValueError
return eTree pt = buildParseTree("( ( 10 + 5 ) * 3 )")
pp= pt.postorder() #defined and explained in the next section
输出结果:
{"harold": {"username": "hrldcpr"}, "handler": {"username": "matthandlersux"}}
{'Animalia': {'Chordata': {'Mammalia': {'Carnivora': {'Felidae': {'Panthera': {'lion': {}}, 'Felis': {'cat': {}}}, 'Canidae': {'Canis': {'dog': {}, 'coyote': {}}}}}}}, 'Plantae': {'Solanales': {'Convolvulaceae': {'Ipomoea': {'sweet potato': {}}}, 'Solanaceae': {'Solanum': {'tomato': {}, 'potato': {}}}}}}
10
5
+
3
*
('In', 'the')
('the', 'beginning')
('beginning', 'god')
('god', 'created')
('created', 'the')
('the', 'heaven')
('heaven', 'and')
('and', 'the')
('the', 'earth')
('earth', '.')
涂聚文,geovindu
geovindu-PC
192.168.20.210
hello word 你好,世界
win32
1267650600228229401496703205376
输入的内容:
2.
import uuid; #Python3.5 class TreeNode(object):
def __init__(self, data = -1, lchild = None, rchild = None):
self.data = data
self.lchild = lchild
self.rchild = rchild class BinaryTree(object):
def __init__(self):
self.root = TreeNode() def add(self, data):
node = TreeNode(data)
if self.isEmpty():
self.root = node
else:
tree_node = self.root
queue = []
queue.append(self.root) while queue:
tree_node = queue.pop(0)
if tree_node.lchild == None:
tree_node.lchild = node
return
elif tree_node.rchild == None:
tree_node.rchild = node
return
else:
queue.append(tree_node.lchild)
queue.append(tree_node.rchild) def pre_order(self, start):
node = start
if node == None:
return print(node.data),
if node.lchild == None and node.rchild == None:
return
self.pre_order(node.lchild)
self.pre_order(node.rchild) def pre_order_loop(self):
if self.isEmpty():
return stack = []
node = self.root
while node or stack:
while node:
print(node.data),
stack.append(node)
node = node.lchild
if stack:
node = stack.pop()
node = node.rchild def in_order(self, start):
node = start
if node == None:
return
self.in_order(node.lchild)
print(node.data),
self.in_order(node.rchild) def in_order_loop(self):
if self.isEmpty():
return stack = []
node = self.root
while node or stack:
while node:
stack.append(node)
node = node.lchild if stack:
node = stack.pop()
print(node.data),
node = node.rchild def post_order(self, start):
node = start
if node == None:
return
self.post_order(node.lchild)
self.post_order(node.rchild)
print(node.data), def post_order_loop(self):
if self.isEmpty():
return node = self.root
stack = []
queue = []
queue.append(node)
while queue:
node = queue.pop()
if node.lchild:
queue.append(node.lchild)
if node.rchild:
queue.append(node.rchild)
stack.append(node)
while stack:
print(stack.pop().data), #if lchild and rchild are None or lchild and rchild are printed, print the parent node node and pop out of the stack
#else lchild and rchild push into the stack
def post_order_loop1(self):
if self.isEmpty():
return stack = []
top = -1
node = self.root
stack.append(node)
#we need to recognize the last printed node
top += 1
pre = None
while stack:
node = stack[-1]
if node.lchild is None and node.rchild is None:
print(node.data),
pre = node
top -= 1
elif not pre and (node.lchild == pre or node.rchild == pre):
print(node.data),
pre = node
top -= 1
else:
if node.rchild:
if top < len(stack)-1:
stack[top] = node.rchild
else:
stack.append(node.rchild)
if node.lchild:
if top < len(stack)-1:
stack[top] = node.lchild
else:
stack.append(node.lchild) def level_order(self):
node = self.root
if node == None:
return queue = []
queue.append(node) while queue:
node = queue.pop(0)
print(node.data),
if node.rchild:
queue.append(node.rchild)
if node.lchild:
queue.append(node.lchild)
print def isEmpty(self):
return True if self.root.data == -1 else False class NodeTu:
def __init__(self, value, next=None):
self.value = value;
self.next = next; class NodeDu:
def __init__(self, value, left=None, right=None):
self.value = value
self.left = left
self.right = right
测试:
import nltk;
import pandas;
import matplotlib;
import math;
import os;
import unittest;
#from nltk.parse.featurechart import trees
import NodeDu;
import copy;
import NodeTu;
import TreeNode;
from nltk.tree import ParentedTree; #Python 3.5 #from platform import node #1. tree data structure
arr = []
for i in range(10):
arr.append(i)
print(arr); tree =TreeNode.BinaryTree();
for i in arr:
tree.add(i)
print('level_order:');
tree.level_order();
print('pre order:');
tree.pre_order(tree.root)
print('\npre order loop:');
tree.pre_order_loop()
print('\nin_order:');
tree.in_order(tree.root)
print('\nin_order loop:');
tree.in_order_loop()
print('\npost_order:');
tree.post_order(tree.root)
print('\npost_order_loop:');
tree.post_order_loop()
print('\npost_order_loop1:');
tree.post_order_loop1() a11=NodeTu.NodeTu(6);
a12=NodeTu.NodeTu(5);
a13=NodeTu.NodeTu(4);
a14=NodeTu.NodeTu(3);
a15=NodeTu.NodeTu(2); a12=a11.next;
a13=a14.next;
a14=a15.next; a16=a11.next; print(a15.value);
print(a11.value); a1 = NodeDu.NodeDu(6);
b1 = NodeDu.NodeDu(5);
b2 = NodeDu.NodeDu(2);
c1 = NodeDu.NodeDu(4);
c2 = NodeDu.NodeDu(1);
c3 = NodeDu.NodeDu(1);
d1 = NodeDu.NodeDu(3);
d2 = NodeDu.NodeDu(0); a1.left = b1;
a1.right = b2;
b1.left = c1;
b1.right = c2;
b2.left = c3;
c1.left = d1;
c1.right = d2; s = []; def gos(node, path=[]):
if node:
path.append(node.value)
if node.left:
path1 = copy.copy(path)
gos(node.left, path1)
if node.right:
path2 = copy.copy(path)
gos(node.right, path2)
else:
s.append(copy.copy(path)) gos(a1);
print(s); #
ptree = ParentedTree.fromstring('(ROOT (S (NP (JJ Congressional) \
(NNS representatives)) (VP (VBP are) (VP (VBN motivated) \
(PP (IN by) (NP (NP (ADJ shiny) (NNS money))))))) (. .))') def traverse(t):
try:
t.label()
except AttributeError:
return
else:
if t.height() == 2: #child nodes
print(t.parent());
return for child in t:
traverse(child) tra=traverse(ptree);
print(tra); ptree = ParentedTree.fromstring('(ROOT (S (NP (PRP It)) \
(VP (VBZ is) (ADJP (RB so) (JJ nice))) (. .)))') leaf_values = ptree.leaves(); if 'nice' in leaf_values:
leaf_index = leaf_values.index('nice')
tree_location = ptree.leaf_treeposition(leaf_index)
print(tree_location);
print(ptree[tree_location]);
输出:
[0, 1, 2, 3, 4, 5, 6, 7, 8, 9]
level_order:
0
2
1
6
5
4
3
9
8
7
pre order:
0
1
3
7
8
4
9
2
5
6
pre order loop:
0
1
3
7
8
4
9
2
5
6
in_order:
7
3
8
1
9
4
0
5
2
6
in_order loop:
7
3
8
1
9
4
0
5
2
6
post_order:
7
8
3
9
4
1
5
6
2
0
post_order_loop:
7
8
3
9
4
1
5
6
2
0
post_order_loop1:
https://repo.continuum.io/archive/.winzip/
https://github.com/Rochester-NRT/RocAlphaGo
https://github.com/wrongu/
https://github.com/hiropppe/
https://gitter.im/Rochester-NRT/RocAlphaGo
http://www.nltk.org/nltk_data/
Python: tree data structure的更多相关文章
- [Algorithms] Tree Data Structure in JavaScript
In a tree, nodes have a single parent node and may have many children nodes. They never have more th ...
- 树状结构 Tree data structure in C#
delegate void TreeVisitor<T>(T nodeData); class NTree<T> { private T data; private Linke ...
- CDOJ 483 Data Structure Problem DFS
Data Structure Problem Time Limit: 20 Sec Memory Limit: 256 MB 题目连接 http://acm.uestc.edu.cn/#/proble ...
- 字典树(查找树) leetcode 208. Implement Trie (Prefix Tree) 、211. Add and Search Word - Data structure design
字典树(查找树) 26个分支作用:检测字符串是否在这个字典里面插入.查找 字典树与哈希表的对比:时间复杂度:以字符来看:O(N).O(N) 以字符串来看:O(1).O(1)空间复杂度:字典树远远小于哈 ...
- LeetCode208 Implement Trie (Prefix Tree). LeetCode211 Add and Search Word - Data structure design
字典树(Trie树相关) 208. Implement Trie (Prefix Tree) Implement a trie with insert, search, and startsWith ...
- 211. Add and Search Word - Data structure design
题目: Design a data structure that supports the following two operations: void addWord(word) bool sear ...
- [LeetCode] 211. Add and Search Word - Data structure design 添加和查找单词-数据结构设计
Design a data structure that supports the following two operations: void addWord(word) bool search(w ...
- 【LeetCode】211. Add and Search Word - Data structure design 添加与搜索单词 - 数据结构设计
作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 公众号:负雪明烛 本文关键词:Leetcode, 力扣,211,搜索单词,前缀树,字典树 ...
- [LeetCode] Add and Search Word - Data structure design 添加和查找单词-数据结构设计
Design a data structure that supports the following two operations: void addWord(word) bool search(w ...
随机推荐
- Hessian 使用例子
一.协议包(数据对象需要实现序列化接口,可以用于服务端接口.客户端调用服务之用) /** * */ package com.junge.demo.protocol.model; import java ...
- MVC+EF CODE FIRST的使用
1创建标准MVC项目 2通过NuGet安装EF 3在Models文件夹中编写实体类 4创建EFDB上下文类 5在webconfig中创建连接字符串,其中name=EFDB上下文类名 6通过管理控制台执 ...
- Java设计模式----解释器模式
计算器中,我们输入“20 + 10 - 5”,计算器会得出结果25并返回给我们.可你有没有想过计算器是怎样完成四则运算的?或者说,计算器是怎样识别你输入的这串字符串信息,并加以解析,然后执行之,得出结 ...
- Javascript多线程
最近项目中要用一个倒计时,但是当弹窗的时候倒计时会被阻塞,所以我想到使用Javascript多线程解决该问题. 虽然JavaScript是单线程的,但是通过worker可以让Javascript另外开 ...
- ORACLE 日期加减操作
无论是DATE还是timestamp都可以进行加减操作. 可以对当前日期加年.月.日.时.分.秒,操作不同的时间类型,有三种方法: 1 使用内置函数numtodsinterval增加小时,分钟和秒2 ...
- ubuntu环境下编译linux内核问题解决备忘
在使用比较新的gcc编译内核时,经常遇到这个问题: 问题一: 提示: mkimage" command not found - U-Boot images will not be built ...
- 机器学习技法笔记:14 Radial Basis Function Network
Roadmap RBF Network Hypothesis RBF Network Learning k-Means Algorithm k-Means and RBF Network in Act ...
- Redis最新面试题26题(初级、中级Redis面试题)
Redis 1级(入门基础) 1.Redis有哪些数据类型? string,list,set,sorted set(Zset),hash 2.集合和列表有什么区别? 列表是可以从两端推入.推出数据的队 ...
- 转载 Python中关键字global与nonlocal的区别
转载自CSDN 雁丘1990, 原文地址: https://blog.csdn.net/xcyansun/article/details/79672634 这篇文章写的很赞, 条理清晰, 分析循序渐进 ...
- JavaScript “跑马灯”抽奖活动代码解析与优化(二)
既然是要编写插件.那么叫做"插件"的东西肯定是具有的某些特征能够满足我们平时开发的需求或者是提高我们的开发效率.那么叫做插件的东西应该具有哪些基本特征呢?让我们来总结一下: 1.J ...