LeetCode 455. Assign Cookies （分发曲奇饼干）

Assume you are an awesome parent and want to give your children some cookies. But, you should give each child at most one cookie. Each child i has a greed factor gi, which is the minimum size of a cookie that the child will be content with; and each cookie j has a size sj. If sj >= gi, we can assign the cookie j to the child i, and the child i will be content. Your goal is to maximize the number of your content children and output the maximum number.

Note:
You may assume the greed factor is always positive. 
You cannot assign more than one cookie to one child.

Example 1:

Input: [1,2,3], [1,1]

Output: 1

Explanation: You have 3 children and 2 cookies. The greed factors of 3 children are 1, 2, 3.
And even though you have 2 cookies, since their size is both 1, you could only make the child whose greed factor is 1 content.
You need to output 1.

Example 2:

Input: [1,2], [1,2,3]

Output: 2

Explanation: You have 2 children and 3 cookies. The greed factors of 2 children are 1, 2.
You have 3 cookies and their sizes are big enough to gratify all of the children,
You need to output 2.

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题目标签：Greedy

　　这道题目给了我们两组array，一组代表小朋友的胃口值，另一组代表曲奇饼干的大小。我们要分发曲奇给尽可能多的小朋友，并且曲奇饼干的大小是可以满足小朋友的胃口的。

所以我们不能把大的曲奇去满足很小胃口的小朋友，除非没有选择。尽可能的去把小曲奇发给小胃口的小朋友。首先把两个array 重新排列，从小到大。然后遍历曲奇array，找到可以满足的小朋友，发给他曲奇，记住他的index，下次就直接从下一个小朋友开始找。

 

 

Java Solution:

Runtime beats 57.78%

完成日期：06/24/2017

关键词：Greedy

关键点：把array重新排序

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 public class Solution
 {
     public int findContentChildren(int[] g, int[] s)
     {
         int res = 0;
         int index_g = 0;
         Arrays.sort(g);
         Arrays.sort(s);

         for(int i=0; i< s.length; i++)
         {
             if(s[i] >= g[index_g])
             {
                 res++;
                 index_g++;

                 if(index_g >= g.length)
                     break;
             }
         }

         return res;
     }
 }

参考资料：N / A

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