Bipin Joshi (http://www.binaryintellect.net/articles/f1cee257-378a-42c1-9f2f-075a3aed1d98.aspx)


Uploading files is a common requirement in web applications. In ASP.NET Core 1.0 uploading files and saving them on the server is quite easy. To that end this article shows how to do just that.Begin by creating a new ASP.NET Core project. Then add HomeController to the controllers folder. Then add UploadFiles view to Views > Home folder of the application.

HTML form for uploading files

Open the UploadFiles view and add the following HTML markup in it:

   1: <form asp-action="UploadFiles" 

   2:       asp-controller="Home" 

   3:       method="post"

   4:       enctype="multipart/form-data">

   5:     <input type="file" name="files" multiple />

   6:     <input type="submit" value="Upload Selected Files" />

   7: </form>

The above markup uses form tag helper of ASP.NET Core MVC. The asp-action attribute indicates that the form will be processed by the UploadFiles action upon submission. The asp-controller attribute specifies the name of the controller containing the action method. The form is submitted using POST method. The enctype attribute of the form is set to multipart/form-data indicating that it will be used for file upload operation.

The form contains an input field of type file. The name attribute of the file input field is set to files and the presence of multiple attribute indicates that multiple files can be uploaded at once. The submit button submits the form to the server.

If you run the application at this stage, the UploadFiles view should look like this:

aaarticlea/png;base64,iVBORw0KGgoAAAANSUhEUgAAAAEAAAABCAIAAACQd1PeAAAAGXRFWHRTb2Z0d2FyZQBBZG9iZSBJbWFnZVJlYWR5ccllPAAAAyBpVFh0WE1MOmNvbS5hZG9iZS54bXAAAAAAADw/eHBhY2tldCBiZWdpbj0i77u/IiBpZD0iVzVNME1wQ2VoaUh6cmVTek5UY3prYzlkIj8+IDx4OnhtcG1ldGEgeG1sbnM6eD0iYWRvYmU6bnM6bWV0YS8iIHg6eG1wdGs9IkFkb2JlIFhNUCBDb3JlIDUuMC1jMDYwIDYxLjEzNDc3NywgMjAxMC8wMi8xMi0xNzozMjowMCAgICAgICAgIj4gPHJkZjpSREYgeG1sbnM6cmRmPSJodHRwOi8vd3d3LnczLm9yZy8xOTk5LzAyLzIyLXJkZi1zeW50YXgtbnMjIj4gPHJkZjpEZXNjcmlwdGlvbiByZGY6YWJvdXQ9IiIgeG1sbnM6eG1wPSJodHRwOi8vbnMuYWRvYmUuY29tL3hhcC8xLjAvIiB4bWxuczp4bXBNTT0iaHR0cDovL25zLmFkb2JlLmNvbS94YXAvMS4wL21tLyIgeG1sbnM6c3RSZWY9Imh0dHA6Ly9ucy5hZG9iZS5jb20veGFwLzEuMC9zVHlwZS9SZXNvdXJjZVJlZiMiIHhtcDpDcmVhdG9yVG9vbD0iQWRvYmUgUGhvdG9zaG9wIENTNSBXaW5kb3dzIiB4bXBNTTpJbnN0YW5jZUlEPSJ4bXAuaWlkOkJDQzA1MTVGNkE2MjExRTRBRjEzODVCM0Q0NEVFMjFBIiB4bXBNTTpEb2N1bWVudElEPSJ4bXAuZGlkOkJDQzA1MTYwNkE2MjExRTRBRjEzODVCM0Q0NEVFMjFBIj4gPHhtcE1NOkRlcml2ZWRGcm9tIHN0UmVmOmluc3RhbmNlSUQ9InhtcC5paWQ6QkNDMDUxNUQ2QTYyMTFFNEFGMTM4NUIzRDQ0RUUyMUEiIHN0UmVmOmRvY3VtZW50SUQ9InhtcC5kaWQ6QkNDMDUxNUU2QTYyMTFFNEFGMTM4NUIzRDQ0RUUyMUEiLz4gPC9yZGY6RGVzY3JpcHRpb24+IDwvcmRmOlJERj4gPC94OnhtcG1ldGE+IDw/eHBhY2tldCBlbmQ9InIiPz6p+a6fAAAAD0lEQVR42mJ89/Y1QIABAAWXAsgVS/hWAAAAAElFTkSuQmCC" alt="" />

Constructor and UploadFiles() GET action

Now, open the HomeController and add a constructor to it as shown below:

   1: public class HomeController : Controller

   2: {

   3:     private IHostingEnvironment hostingEnv;

   4:     public HomeController(IHostingEnvironment env)

   5:     {

   6:         this.hostingEnv = env;

   7:     }

   8: }

The constructor has a parameter of type IHostingEnvironment (Microsoft.AspNet.Hosting namespace). This parameter will be injected by MVC framework into the constructor. You need this parameter to construct the full path for saving the uploaded files. The IHostingEnvironment object is saved into a local variable for later use.

Then add UploadFiles() action for GET requests as shown below:

   1: public IActionResult UploadFiles()

   2: {

   3:     return View();

   4: }

UploadFiles() POST action

Finally, add UploadFiles() action for handling the POST requests.

   1: [HttpPost]

   2: public IActionResult UploadFiles(IList<IFormFile> files)

   3: {

   4:     long size = 0;

   5:     foreach(var file in files)

   6:     {

   7:         var filename = ContentDispositionHeaderValue

   8:                         .Parse(file.ContentDisposition)

   9:                         .FileName

  10:                         .Trim('"');

  11:         filename = hostingEnv.WebRootPath + $@"\{fileName}";

  12:         size += file.Length;

  13:         using (FileStream fs = System.IO.File.Create(filename))

  14:         {

  15:            file.CopyTo(fs);

  16:            fs.Flush();

  17:         }

  18:     }

  19:  

  20:     ViewBag.Message = $"{files.Count} file(s) / 

  21:                       {size} bytes uploaded successfully!";

  22:     return View();

  23: }

The UploadFiles() action has a parameter - IList<IFormFile> - to receive the uploaded files. The IFormFile object represents a single uploaded file. Inside, a size variable keeps track of how much data is being uploaded. Then a foreach loop iterates through the files collection.

The client side file name of an uploaded file is extracted using the ContentDispositionHeaderValue class (Microsoft.Net.Http.Headers namespace) and the ContentDisposition property of the IFormFile object. Let's assume that you wish to save the uploaded files into the wwwroot folder. So, to arrive at the full path you use the WebRootPath property of IHostingEnvironment and append the filename to it.

Finally, the file is saved by the code inside the using block. That code basically creates a new FileStream and copies the uploaded file into it. This is done using the Create() and the CopyTo() methods. A message is stored in ViewBag to be displayed to the end user.

The following figure shows a sample successful run of the application:

aaarticlea/png;base64,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" alt="" />

Using jQuery Ajax to upload the files

In the preceding example you used form POST to submit the files to the server. What if you wish to send files through Ajax? You can accomplish the task with a little bit of change to the <form> and the action.

Modify the <form> to have a plain push button instead of submit button as shown below:

   1: <form method="post" enctype="multipart/form-data">

   2:     <input type="file" id="files" 

   3:            name="files" multiple />

   4:     <input type="button" 

   5:            id="upload" 

   6:            value="Upload Selected Files" />

   7: </form>

Then add a <script> reference to the jQuery library and write the following code to handle the click event of the upload button:

   1: $(document).ready(function () {

   2:     $("#upload").click(function (evt) {

   3:         var fileUpload = $("#files").get(0);

   4:         var files = fileUpload.files;

   5:         var data = new FormData();

   6:         for (var i = 0; i < files.length ; i++) {

   7:             data.append(files[i].name, files[i]);

   8:         }

   9:         $.ajax({

  10:             type: "POST",

  11:             url: "/home/UploadFilesAjax",

  12:             contentType: false,

  13:             processData: false,

  14:             data: data,

  15:             success: function (message) {

  16:                 alert(message);

  17:             },

  18:             error: function () {

  19:                 alert("There was error uploading files!");

  20:             }

  21:         });

  22:     });

  23: });

The above code grabs each file from the file field and adds it to a FormData object (HTML5 feature). Then $.ajax() method POSTs the FormData object to the UploadFilesAjax() action of the HomeController. Notice that the contentType and processData properties are set to false since the FormData contains multipart/form-data content. The data property holds the FormData object.

Finally, add UploadFilesAjax() action as follows:

   1: [HttpPost]

   2: public IActionResult UploadFilesAjax()

   3: {

   4:     long size = 0;

   5:     var files = Request.Form.Files;

   6:     foreach (var file in files)

   7:     {

   8:         var filename = ContentDispositionHeaderValue

   9:                         .Parse(file.ContentDisposition)

  10:                         .FileName

  11:                         .Trim('"');

  12:         filename = hostingEnv.WebRootPath + $@"\{filename}";

  13:         size += file.Length;

  14:         using (FileStream fs = System.IO.File.Create(filename))

  15:         {

  16:            file.CopyTo(fs);

  17:            fs.Flush();

  18:         }

  19:     }

  20:     string message = $"{files.Count} file(s) / 

  21:                        {size} bytes uploaded successfully!";

  22:     return Json(message);

  23: }

The code inside UploadFilesAjax() is quite similar to UploadFiles() you wrote earlier. The main difference is how the files are received. The UploadFilesAjax() doesn't have IList<IFormFile> parameter. Instead it receives the files through the Request.Form.Files property. Secondly, the UploadFilesAjax() action returns a JSON string message to the caller for the sake of displaying in the browser.

That's it for now! Keep coding!!

ASP.NET Core 1.0中实现文件上传的两种方式(提交表单和采用AJAX)的更多相关文章

  1. curl文件上传有两种方式,一种是post_fileds,一种是infile

    curl文件上传有两种方式,一种是POSTFIELDS,一种是INFILE,POSTFIELDS传递@实际地址,INFILE传递文件流句柄! );curl_setopt($ch, CURLOPT_PO ...

  2. 用VSCode开发一个asp.net core2.0+angular5项目(5): Angular5+asp.net core 2.0 web api文件上传

    第一部分: http://www.cnblogs.com/cgzl/p/8478993.html 第二部分: http://www.cnblogs.com/cgzl/p/8481825.html 第三 ...

  3. Asp.Net Core 2.0 WebUploader FastDfs 文件上传 分段上传

    功能点: 1. 使用.net core 2.0 实现文件上传 2. 使用webuploader实现单文件,多文件上传 3. 使用webuploader实现大文件的分段上传. 4. 使用webuploa ...

  4. 利用Selenium实现图片文件上传的两种方式介绍

    在实现UI自动化测试过程中,有一类需求是实现图片上传,这种需求根据开发的实现方式,UI的实现方式也会不同. 一.直接利用Selenium实现 这种方式是最简单的一种实现方式,但是依赖于开发的实现. 当 ...

  5. ASP.NET Core WEB API 使用element-ui文件上传组件el-upload执行手动文件文件,并在文件上传后清空文件

    前言: 从开始学习Vue到使用element-ui-admin已经有将近快两年的时间了,在之前的开发中使用element-ui上传组件el-upload都是直接使用文件选取后立即选择上传,今天刚好做了 ...

  6. java模拟表单上传文件,java通过模拟post方式提交表单实现图片上传功能实例

    java模拟表单上传文件,java通过模拟post方式提交表单实现图片上传功能实例HttpClient 测试类,提供get post方法实例 package com.zdz.httpclient; i ...

  7. Java文件上传的几种方式

    文件上传与文件上传一样重要.在Java中,要实现文件上传,可以有两种方式: 1.通过Servlet类上传 2.通过Struts框架实现上传 这两种方式的根本还是通过Servlet进行IO流的操作. 一 ...

  8. web 文件上传的几种方式

    问题 文件上传在WEB开发中应用很广泛. 文件上传是指将本地图片.视频.音频等文件上传到服务器上,可以供其他用户浏览或下载的过程. 以下总结了常见的文件(图片)上传的方式和要点处理. 表单上传 这是传 ...

  9. 基础教程:上传/下载ASP.NET Core 2.0中的文件

    问题 如何上传和下载ASP.NET Core MVC中的文件. 解 在一个空的项目中,更新 Startup 类以添加MVC的服务和中间件. publicvoid ConfigureServices( ...

随机推荐

  1. 【.net 深呼吸】细说CodeDom(4):类型定义

    上一篇文章中说了命名空间,你猜猜接下来该说啥.是了,命名空间下面就是类型,知道了如何生成命名空间的定义代码,之后就该学会如何声明类型了. CLR的类型通常有这么几种:类.接口.结构.枚举.委托.是这么 ...

  2. webapi - 使用依赖注入

    本篇将要和大家分享的是webapi中如何使用依赖注入,依赖注入这个东西在接口中常用,实际工作中也用的比较频繁,因此这里分享两种在api中依赖注入的方式Ninject和Unity:由于快过年这段时间打算 ...

  3. 学点HTTP知识

    不学无术 又一次感觉到不学无术,被人一问Http知识尽然一点也没答上来,丢人丢到家了啊.平时也看许多的技术文章,为什么到了关键时刻就答不上来呢? 确实发现一个问题,光看是没有用的,需要实践.看别人说的 ...

  4. Jquery的事件操作和文档操作

    对于熟悉前端开发的小伙伴,相信对于Jquery一定不陌生,相对于JavaScript的繁琐,Jquery更加的简洁,当然简洁不意味着简单,我们可以使用Jquery完成我们想要实现全部功能,这里为小白们 ...

  5. zookeeper源码分析之六session机制

    zookeeper中session意味着一个物理连接,客户端连接服务器成功之后,会发送一个连接型请求,此时就会有session 产生. session由sessionTracker产生的,sessio ...

  6. javascript设计模式:策略模式

    前言 策略模式有效利用组合.委托.多态等技术和思想,可以有效避免多重条件选择语句. 策略模式对开放-封闭原则提供了很好的支持,将算法封装在strategy中,使得他们易于切换.理解.扩展. 策略模式中 ...

  7. sql的那些事(一)

    一.概述 书写sql是我们程序猿在开发中必不可少的技能,优秀的sql语句,执行起来吊炸天,性能杠杠的.差劲的sql,不仅使查询效率降低,维护起来也十分不便.一切都是为了性能,一切都是为了业务,你觉得你 ...

  8. input type='file'上传控件假样式

    采用bootstrap框架样式 <!DOCTYPE html> <html xmlns="http://www.w3.org/1999/xhtml"> &l ...

  9. [转载]一个标准java程序员的进阶过程

    第一阶段:Java程序员 技术名称 内                 容 说明 Java语法基础 基本语法.数组.类.继承.多态.抽象类.接口.object对象.常用类(Math\Arrarys\S ...

  10. Angular (SPA) WebPack模块化打包、按需加载解决方案完整实现

    文艺小说-?2F,言情小说-?3F,武侠小说-?9F long long ago time-1-1:A 使用工具,long long A ago time-1-2:A 使用分类工具,long long ...