Django_文件下载

一、小文件下载

1、视图 views.py

三种方式实现，任选其一

（1）使用HttpResponse

# 导入模块
from django.shortcuts import HttpResponse
def download(request):
　　file = open('crm/models.py', 'rb')
　　response = HttpResponse(file)
　　response['Content-Type'] = 'application/octet-stream' #设置头信息，告诉浏览器这是个文件
　　response['Content-Disposition'] = 'attachment;filename="models.py"'
　　return response

（2）使用StreamingHttpResponse

from django.http import StreamingHttpResponse
def download(request):
　　file=open('crm/models.py','rb')
　　response =StreamingHttpResponse(file)
　　response['Content-Type']='application/octet-stream'
　　response['Content-Disposition']='attachment;filename="models.py"'
　　return response

（3）使用FileResponse

from django.http import FileResponse
def download(request):
    file=open('crm/models.py','rb')
    response =FileResponse(file)
    response['Content-Type']='application/octet-stream'
    response['Content-Disposition']='attachment;filename="models.py"'
    return response

2、添加路由 urls.py

配置一个下载的路径

url(r'^download/',views.download,name="download"),

3、模板 templates 的修改

配置一个 a 标签，跳转地址配置要跳转的下载路径（对应的视图）

<div class="col-md-4"><a href="{% url 'download' %}" rel="external nofollow" >点我下载</a></div>

二、大文件下载

大文件需要使用迭代器优化

只需要修改 views.py 文件

from django.http import StreamingHttpResponse

def download(request):
　　def file_iterator(file_name, chunk_size=512):
   　　with open(file_name, 'rb') as f:
      　　while True:
         　　c = f.read(chunk_size)
            　　if c:
               　　yield c
               else:
                  break
 　　the_file_name = 'static/images/exam/logo.png'
 　　response = StreamingHttpResponse(file_iterator(the_file_name))
 　　response['Content-Type'] = 'application/octet-stream'
 　　response['Content-Disposition'] = 'attachment;filename="{0}"'.format(the_file_name)
　　 return response