Python---基础---爱因斯坦阶梯问题

写一个程序，打印出0-100所有奇数

ls = range(0, 101)
for i in ls:
    if i % 2 == 1:
        print(i)
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爱因斯坦曾出过这样一道有趣的数学题：有一个长阶梯，走每步上2阶，最后剩余1阶；如果每步上3阶，最后剩2阶；若每步上5阶，最后剩4阶；若每步上6阶，最后剩5阶，
只有每步上7阶，最后刚好一阶不剩。
-编写程序求该阶梯至少有多少阶

x = 10
while x < 1000:
    if (x % 2 == 1) and (x % 3 == 2) and (x % 5 == 4) and (x % 6 == 5) and (x % 7 ==0):
        print(x)
        x += 1
        #break;
    else:
        x += 1

print("循环结束")
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x = 10
while x < 1000:
    if (x % 2 == 1) \
    and (x % 3 == 2) \
    and (x % 5 == 4) \
    and (x % 6 == 5) \
    and (x % 7 ==0):
        print(x)
        x += 1
        #break;
    else:
        x += 1

print("循环结束")
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