利用row_number over 函数删除重复记录
开窗函数
Oracle从8.1.6开始提供分析函数,分析函数用于计算基于组的某种聚合值,它和聚合函数的不同之处是:对于每个组返回多行,而聚合函数对于每个组只返回一行
SQL> create table a1(id int,flag1 char(10),flag2 char(10));
Table created.
SQL> select * from a1;
ID FLAG1 FLAG2
---------- ---------- ----------
1 a a1
1 a a2
1 b b1
1 b b2
SQL> delete from (select unique a.* from a1 a);
delete from (select unique a.* from a1 a)
*
ERROR at line 1:
ORA-01732: data manipulation operation not legal on this view
SQL> delete from (select * from (select unique a.* from a1 a));
delete from (select * from (select unique a.* from a1 a))
*
ERROR at line 1:
ORA-01752: cannot delete from view without exactly one key-preserved table
SQL> delete from (select * from a1 group by id,name);
delete from (select * from a1 group by id,name)
*
ERROR at line 1:
ORA-01732: data manipulation operation not legal on this view
SQL> select a.*,row_number() over(partition by id,flag1 order by id,flag1) as num from a1 a;
ID FLAG1 FLAG2 NUM
---------- ---------- ---------- ----------
1 a a1 1
1 a a2 2
1 b b1 1
1 b b2 2
SQL> delete from (select a.*,row_number() over(partition by id,flag1 order by id,flag1) as num from a1 a) where num>1;
delete from (select a.*,row_number() over(partition by id,flag1 order by id,flag1) as num from a1 a) where num>1
*
ERROR at line 1:
ORA-01732: data manipulation operation not legal on this view
SQL> (select a.*,
row_number() over(partition by id, flag1 order by id, flag1) as num
from a1 a) 2 3 ;
ID FLAG1 FLAG2 NUM
---------- ---------- ---------- ----------
1 a a1 1
1 a a2 2
1 b b1 1
1 b b2 2
SQL> delete from a1 where rowid in (select rowid
from (select a.*,
row_number() over(partition by id, flag1 order by id, flag1) as num
from a1 a)a
where num >= 2) 2 3 4 5
6 ;
2 rows deleted.
SQL> commit;
Commit complete.
SQL> select * from a1;
ID FLAG1 FLAG2
---------- ---------- ----------
1 a a1
1 b b1
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