Commando War (贪心)
Waiting for orders we held in the wood, word from the front never came
By evening the sound of the gunfire was miles away
Ah softly we moved through the shadows, slip away through the trees
Crossing their lines in the mists in the fields on our hands and our knees
And all that I ever, was able to see
The fire in the air, glowing red, silhouetting the smoke on the breeze
There is a war and it doesn't look very promising for your country. Now it's time to act. You have a commando squad at your disposal and planning an ambush on an important enemy camp located nearby. You have N soldiers in your squad. In your master-plan, every single soldier has a unique responsibility and you don't want any of your soldier to know the plan for other soldiers so that everyone can focus on his task only. In order to enforce this, you brief every individual soldier about his tasks separately and just before sending him to the battlefield. You know that every single soldier needs a certain amount of time to execute his job. You also know very clearly how much time you need to brief every single soldier. Being anxious to finish the total operation as soon as possible, you need to find an order of briefing your soldiers that will minimize the time necessary for all the soldiers to complete their tasks. You may assume that, no soldier has a plan that depends on the tasks of his fellows. In other words, once a soldier begins a task, he can finish it without the necessity of pausing in between.
Input
There will be multiple test cases in the input file. Every test case starts with an integer N (1<=N<=1000), denoting the number of soldiers. Each of the following N lines describe a soldier with two integers B (1<=B<=10000) & J (1<=J<=10000). B seconds are needed to brief the soldier while completing his job needs J seconds. The end of input will be denoted by a case with N =0 . This case should not be processed.
Output
For each test case, print a line in the format, Case X: Y, where X is the case number & Y is the total number of seconds counted from the start of your first briefing till the completion of all jobs.
Sample Input Output for Sample Input
3
2 5
3 2
2 1
3
3 3
4 4
5 5
0
Case 1: 8
Case 2: 15
题解:贪心,按执行任务的时间从大到小排,得到的就是最优解
代码:
#include<cstdio>
#include<cstring>
#include<iostream>
#include<algorithm>
using namespace std;
struct node
{
int b,j;
}p[1005];
bool cmp(node x,node y)
{
return x.j>y.j;
}
int main()
{
int N;
int cnt=1;
while(scanf("%d",&N)&&N)
{
for(int t=0;t<N;t++)
{
scanf("%d%d",&p[t].b,&p[t].j);
}
sort(p,p+N,cmp);
long long int s=0,sum=0;
for(int t=0;t<N;t++)
{
s+=p[t].b;
sum=max(sum,s+p[t].j);
}
printf("Case %d: %lld\n",cnt++,sum);
}
}
Commando War (贪心)的更多相关文章
- UVa 11729 - Commando War(贪心)
"Waiting for orders we held in the wood, word from the front never came By evening the sound of ...
- UVA 11729 - Commando War(贪心 相邻交换法)
Commando War There is a war and it doesn't look very promising for your country. Now it's time to ac ...
- Uva 11729 Commando War (简单贪心)
Uva 11729 Commando War (简单贪心) There is a war and it doesn't look very promising for your country. N ...
- 贪心 UVA 11729 Commando War
题目传送门 /* 贪心:按照执行时间长的优先来排序 */ #include <cstdio> #include <algorithm> #include <iostrea ...
- uva----11729 Commando war (突击战争)
G Commando War Input: Standard Input Output: Standard Output “Waiting for orders we held in the wood ...
- cogs 1446. [Commando War,Uva 11729]突击战
1446. [Commando War,Uva 11729]突击战 ★ 输入文件:commando.in 输出文件:commando.out 简单对比时间限制:1 s 内存限制:64 ...
- Commando War
Commando War“Waiting for orders we held in the wood, word from the front never cameBy evening the so ...
- [ACM_水题] UVA 11729 Commando War [不可同时交代任务 可同时执行 最短完成全部时间 贪心]
There is a war and it doesn't look very promising for your country. Now it's time to act. You have a ...
- 【贪心】【Uva11729】 Commando War
你有n个部下,每个部下需要完成一项任务.第i个部下需要你花Bi分钟交待任务,然后他会立刻独立地.无间断地执行Ji分钟后完成任务.你需要选择交待任务的顺序,使得所有任务尽早执行完毕(即最后一个执行完的任 ...
随机推荐
- “随手记”开发记录day02
今天完成了 向瑜- 布局: 1.修改日期(√) 2.选择分类(√) 3.输入金额(√) 赵常恒- 1.登录,注册页面布局(√) 刘志霄- 1.个人信息页面规划(√)
- Layui+MVC+EF (项目从新创建开始)
最近学习Layui ,就准备通过Layui来实现之前练习的项目, 先创建一个新的Web 空项目,选MVC 新建项目 创建各种类库,模块之间添加引用,并安装必要Nuget包(EF包) 模块名称 模块 ...
- 3、Java 对象和类
1.理解Java中的类和对象 对象: 作为学习计算机专业的很有意思,跟朋友开玩笑说,我有很多对象,没有就new一个.对象可以说是类的实例,通过类的构造方法得到的一个对象实例.它拥有此对象应有的行为与方 ...
- JavaFX桌面应用-为什么应用老是“未响应”
日常使用软件的过程中,偶尔会遇到软件突然卡住,再点击几次就变成"未响应"的情况. 在JavaFX应用中同样也会出现这种情况,在开发过程中应该尽量避免这种情况的出现. >> ...
- java开发在线下载功能,自动打开浏览器下载功能下载网络文件或图片
因为业务的需要,公司产品要求商品详情页面有个下载的功能 找了很多的方法,发现有的需要打开一个新窗口,而且在某些浏览器上不适用,所以继续寻找更好的方法 跟同事沟通后发现他那里有个下载的方法,不过是C#写 ...
- SqlServer 版本号
RTM (no SP) SP1 SP2 SP3 SP4 SQL Server 2014 codename Hekaton 12.00.2000.8 SQL Server 2012 ...
- Qt之先用了再说系列-定时器的用法
Qt 定时器是一个比好用的东西,在此就地简单记录一下使用的方式: 1.首先包含头文件 #include <QTimer> 2.具体用法有几种,我就写其中2种吧 1>执行一次 这种方式 ...
- C#算法设计排序篇之10-桶排序(附带动画演示程序)
桶排序(Bucket Sort) 该文章的最新版本已迁移至个人博客[比特飞],单击链接 https://www.byteflying.com/archives/693 访问. 桶排序的工作原理是将数组 ...
- C#LeetCode刷题-数学
数学篇 # 题名 刷题 通过率 难度 2 两数相加 29.0% 中等 7 反转整数 C#LeetCode刷题之#7-反转整数(Reverse Integer) 28.6% 简单 8 字符串转整数 ...
- 坚持第一天:HashMap和Hashtable的区别
其实,到底是用HashMap和Hashtable主要看需求, 1.它们俩都共同实现了:Map接口,但是Hashtable实现是基于Dictionary抽象类的,在java5的时候提供了Concurre ...