http://accountingexplained.com/financial/inventories/avco-method
 
Average Cost (AVCO) Method
 

Average cost method (AVCO) calculates the cost of ending inventory and cost of goods sold for a period on the basis of weighted average cost per unit of inventory. Weighted average cost per unit is calculated using the following formula:

Weighted Average  =  Total Cost of Inventory
Unit Cost Total Units in Inventory

Like FIFO and LIFO methods, AVCO is also applied differently in periodic inventory system and perpetual inventory system. In periodic inventory system, weighted average cost per unit is calculated for the entire class of inventory. It is then multiplied with number of units sold and number of units in ending inventory to arrive at cost of goods sold and value of ending inventory respectively. In perpetual inventory system, we have to calculate the weighted average cost per unit before each sale transaction.

The calculation of inventory value under average cost method is explained with the help of the following example:

Example

Apply AVCO method of inventory valuation on the following information, first in periodic inventory system and then in perpetual inventory system to determine the value of inventory on hand on Mar 31 and cost of goods sold during March.

Mar 1 Beginning Inventory 60 units @ $15.00 per unit
5 Purchase 140 units @ $15.50 per unit
14 Sale 190 units @ $19.00 per unit
27 Purchase 70 units @ $16.00 per unit
29 Sale 30 units @ $19.50 per unit

Solution

AVCO Periodic

Units Available for Sale = 60 + 140 + 70 = 270
Units Sold = 190 + 30 = 220
Units in Ending Inventory = 270 − 220 = 50
       
Weighted Average Unit Cost Units Unit Cost Total
Mar 1 Inventory 60 $15.00 $900
Mar 5 Purchase 140 $15.50 $2,170
27 Purchase 70 $16.00 $1,120
  270 * $15.52 $4,190
* $4,190 ÷ 270      
       
Cost of Goods Sold 220 $15.52 $3,414
Ending Inventory 50 $15.52 $776

AVCO Perpetual

Date Purchases Sales Balance
Units Unit Cost Total Units Unit Cost Total Units Unit Cost Total
Mar 1             60 $15.00 $900
5 140 $15.50 $2,170       60 $15.00 $900
              140 $15.50 $2,170
              200 $15.35 $3,070
14       190 $15.35 $2,916 10 $15.35 $154
27 70 $16.00 $1,190       10 $15.35 $154
              70 $16.00 $1,120
              80 $15.92 $1,274
29       30 $15.92 $478 50 $15.92 $796
31             50 $15.92 $796

Average Cost (AVCO) Method的更多相关文章

  1. 论文解析 "A Non-Local Cost Aggregation Method for Stereo Matching"

    传统的使用窗口的方法缺陷主要在 1.窗口外的像素不能参与匹配判断. 2.在低纹理区域很容易产生错误匹配 论文的主要贡献在代价聚类上(左右图像带匹配点/区域的匹配代价计算),目标是图像内所有点都对该点传 ...

  2. 基于MST的立体匹配及相关改进(A Non-Local Cost Aggregation Method for Stereo Matching)

    怀着很纠结的心情来总结这篇论文,这主要是因为作者提虽然供了源代码,但是我并没有仔细去深究他的code,只是把他的算法加进了自己的项目.希望以后有时间能把MST这一结构自己编程实现!! 论文题目是基于非 ...

  3. Oracle EBS-SQL (CST-1):检查BOM历史成本查询(Average Cost).sql

    select  msi1.segment1                   父件编码, msi1.description                  父件描述, msi1.primary_u ...

  4. 泡泡一分钟: A Linear Least Square Initialization Method for 3D Pose Graph Optimization Problem

    张宁 A Linear Least Square Initialization Method for 3D Pose Graph Optimization Problem "链接:https ...

  5. Odoo13 新变化:存货核算

    Odoo13将于2019年10月发布,本次发布也包含了大量的改进,例如,对存货核算的重构. 去掉了 产品历史价格product.price.history ,增加了 stock valuation l ...

  6. Adding New Functions to MySQL(User-Defined Function Interface UDF、Native Function)

    catalog . How to Add New Functions to MySQL . Features of the User-Defined Function Interface . User ...

  7. UVA 1456 六 Cellular Network

    Cellular Network Time Limit:3000MS     Memory Limit:0KB     64bit IO Format:%lld & %llu Submit S ...

  8. 大规模视觉识别挑战赛ILSVRC2015各团队结果和方法 Large Scale Visual Recognition Challenge 2015

    Large Scale Visual Recognition Challenge 2015 (ILSVRC2015) Legend: Yellow background = winner in thi ...

  9. R语言-聚类与分类

    一.聚类: 一般步骤: 1.选择合适的变量 2.缩放数据 3.寻找异常点 4.计算距离 5.选择聚类算法 6.采用一种或多种聚类方法 7.确定类的数目 8.获得最终聚类的解决方案 9.结果可视化 10 ...

随机推荐

  1. POJ 1651 (区间DP)

    题目链接: http://poj.org/problem?id=1651 题目大意:加分取牌.如果一张牌左右有牌则可以取出,分数为左牌*中牌*右牌.这样最后肯定还剩2张牌.求一个取牌顺序,使得加分最少 ...

  2. POJ 1548 (二分图+最小路径覆盖)

    题目链接:http://poj.org/problem?id=1548 题目大意:给出一张地图上的垃圾,以及一堆机器人.每个机器人可以从左->右,上->下.走完就废.问最少派出多少个机器人 ...

  3. shenyi 语录

    [讲师]沈逸(65480539) 2016-06-08 14:58:42   会centos 转redhat是分分钟的事 [讲师]沈逸(65480539) 2016-06-08 14:58:54 查看 ...

  4. php函数描述及例子

    /** * xml2array() will convert the given XML text to an array in the XML structure. * Link: http://w ...

  5. Scrum会议6(Beta版本)

    组名:天天向上 组长:王森 组员:张政.张金生.林莉.胡丽娜 代码地址:HTTPS:https://git.coding.net/jx8zjs/llk.git SSH:git@git.coding.n ...

  6. Jquery&JS简单选项卡

    结果,如图 为了明显,用绿色+红色 第一步:静态布局 先写html代码和css样式 要点一:  ul li都为块级元素,可以用height,但是里面字体不居中,我们用line-height,即达到居中 ...

  7. DS实验题 Dijkstra算法

    参考:Dijkstra算法 数据结构来到了图论这一章节,网络中的路由算法基本都和图论相关.于是在拿到DS的实验题的时候,决定看下久负盛名的Dijkstra算法. Dijkstra的经典应用是开放最短路 ...

  8. JS实现HTML静态页传值的方法

    JS实现HTML静态页传值的方法 作者:前端开发-武方博 发布:2012-10-29 分类:javascript 阅读:8,735次     此处使用JS方式实现静态页之间值传递,其实很简单,废话不多 ...

  9. C#winfrom中splitContainer的用法

    常用属性 (1).splitContainer不能被鼠标直接点击选中,可通过右击->选择splitContainer选中. (2).属性IsSplitterFixed用于设置拆分器能否移动. ( ...

  10. 20145317彭垚 《Java程序设计》第五次实验报告

    20145317彭垚实验五 Java网络编程及安全 北京电子科技学院(BESTI)实验报告 课程:Java程序设计 班级:1453 指导教师:娄嘉鹏 实验日期:2016.05.06 18:30-21: ...