概率法求解三阶幻方［C语言］

#include <stdio.h>
#include <string.h>
 
int in[]={,,,,,,,,};
int s[];
int re[][];
 
int sum(int su[])
{
    int i,re=;
    for(i=;su[i];i++)
        re+=su[i];
    return re;
}
 
int main()
{
    int i,j,k,count=;
    memset(s,,sizeof(s));
    int SUM = sum(in);
    if(SUM/ != (float)SUM/9.0)
    {
        printf("wrong\n");
        return ;
    }
    for(i=;i<;i++)
        for(j=i+;j<;j++)
            for(k=j+;k<;k++)
            {
                if(in[i]+in[j]+in[k] == (int)SUM/)
                {
                    s[i]++;
                    s[j]++;
                    s[k]++;
                    count++;
                }
            }
    if(count!=)
    {
        printf("wrong\n");
        return ;
    }
    int flag=;
    for(i=;i>=;i--)
    {
        if(s[i]==)    re[][] = in[i];
        if(s[i]== && flag==) { re[][] = in[i]; flag++; }
        else if(s[i]== && flag==) { re[][] = in[i]; flag++; }
        else if(s[i]== && flag==) { re[][] = in[i]; flag++; }
        else if(s[i]== && flag==) { re[][] = in[i]; flag++; }
    }
    if(re[][]+re[][]+re[][]!=(int)SUM/)
    {
        int tmp;
        tmp = re[][];
        re[][] = re[][];
        re[][] = tmp;
    }
    re[][] = (int)SUM/ - re[][] - re[][];
    re[][] = (int)SUM/ - re[][] - re[][];
    re[][] = (int)SUM/ - re[][] - re[][];
    re[][] = (int)SUM/ - re[][] - re[][];
 
    for(i=;i<;i++)
    {
        for(j=;j<;j++)
        {
            printf("%d ",re[i][j]);
        }
        printf("\n");
    }
    return ;
}