Knight Tournament
time limit per test

3 seconds

memory limit per test

256 megabytes

input

standard input

output

standard output

Hooray! Berl II, the king of Berland is making a knight tournament. The king has already sent the message to all knights in the kingdom and they in turn agreed to participate in this grand event.

As for you, you're just a simple peasant. There's no surprise that you slept in this morning and were late for the tournament (it was a weekend, after all). Now you are really curious about the results of the tournament. This time the tournament in Berland
went as follows:

  • There are n knights participating in the tournament. Each knight was assigned his unique number — an integer from 1 to n.
  • The tournament consisted of m fights, in the i-th
    fight the knights that were still in the game with numbers at least li and
    at most rihave
    fought for the right to continue taking part in the tournament.
  • After the i-th fight among all participants of the fight only one knight won — the knight number xi,
    he continued participating in the tournament. Other knights left the tournament.
  • The winner of the last (the m-th) fight (the knight number xm)
    became the winner of the tournament.

You fished out all the information about the fights from your friends. Now for each knight you want to know the name of the knight he was conquered by. We think that the knight number b was
conquered by the knight number a, if there was a fight with both of these knights present and the winner was the knight number a.

Write the code that calculates for each knight, the name of the knight that beat him.

Input

The first line contains two integers nm (2 ≤ n ≤ 3·105; 1 ≤ m ≤ 3·105) —
the number of knights and the number of fights. Each of the following m lines contains three integers li, ri, xi (1 ≤ li < ri ≤ nli ≤ xi ≤ ri) —
the description of the i-th fight.

It is guaranteed that the input is correct and matches the problem statement. It is guaranteed that at least two knights took part in each battle.

Output

Print n integers. If the i-th
knight lost, then the i-th number should equal the number of the knight that beat the knight number i.
If the i-th knight is the winner, then the i-th
number must equal 0.

Sample test(s)
input
4 3
1 2 1
1 3 3
1 4 4
output
3 1 4 0 
input
8 4
3 5 4
3 7 6
2 8 8
1 8 1
output
0 8 4 6 4 8 6 1 
Note

Consider the first test case. Knights 1 and 2 fought the first fight and knight 1 won. Knights 1 and 3 fought the second fight and knight 3 won. The last fight was between knights 3 and 4, knight 4 won.


题意:有n个人參加比赛,共同拥有m场比赛,每场比赛给出l,r,x,表示[l,r]区间内的人都被x打败,问最后每一个人是被谁打败的,输出那个人的编号,冠军输出0.
分析:这题能够用set,也能够用线段树做。
set解题方法:開始时把全部的人都加进去,然后把输了的人从set中删除就可以。
#include<iostream>
#include<set>
#include<cstring>
using namespace std;
const int MAXN = 300010;
int ans[MAXN];
set<int> s;
set<int>::iterator it, it_l, tmp[MAXN];
int main()
{
int n, m, l, r, x, num;
while(cin >> n >> m) {
s.clear();
memset(ans, 0, sizeof(ans));
for(int i = 1; i <= n; i++)
s.insert(i);
for(int i = 0; i < m; i++) {
cin >> l >> r >> x;
it_l = s.lower_bound(l); //寻找開始删除的位置
num = 0;
for(it = it_l; *it <= r && it != s.end(); it++) {
if(*it != x) {
ans[*it] = x;
tmp[num++] = it; //不能直接删,由于每删除一个元素,set会自己主动调整内部结构
}
}
for(int j = 0; j < num; j++)
s.erase(tmp[j]);
}
for(int i = 1; i < n; i++)
cout << ans[i] << " ";
cout << ans[n] << endl;
}
return 0;
}

CodeForce 356A Knight Tournament(set应用)的更多相关文章

  1. CodeForces - 356A Knight Tournament

    http://codeforces.com/problemset/problem/356/A 首先理解题意 每次给出l 和r  在l - r之间还有资格的选手中得出一个胜者 暴力思路: 首先维护还有资 ...

  2. Knight Tournament 合并区间

    Hooray! Berl II, the king of Berland is making a knight tournament. The king has already sent the me ...

  3. Knight Tournament (set)

    Hooray! Berl II, the king of Berland is making a knight tournament. The king has already sent the me ...

  4. CodeForces - 357C Knight Tournament 伪并查集(区间合并)

    Knight Tournament Hooray! Berl II, the king of Berland is making a knight tournament. The king has a ...

  5. D - Knight Tournament(set)

    Problem description Hooray! Berl II, the king of Berland is making a knight tournament. The king has ...

  6. codeforces 357C Knight Tournament(set)

    Description Hooray! Berl II, the king of Berland is making a knight tournament. The king has already ...

  7. 【Codeforces 356A】Knight Tournament

    [链接] 我是链接,点我呀:) [题意] n个人矩形m场比赛 每场比赛由编号为li~ri且之前没有被淘汰的人进行. 已知第i场的winner是xi winner会把这一场其他所有的人都淘汰. 问你n个 ...

  8. Codeforces Round #207 (Div. 1) A. Knight Tournament(STL)

    脑子又卡了...来一发set的,STL真心不熟. #include <stdio.h> #include <string.h> #include <iostream> ...

  9. Knight Tournament

    Codeforces Round #207 (Div. 1) A:http://codeforces.com/problemset/problem/356/A 题意:给你n匹马,然后有m场比赛.每场比 ...

随机推荐

  1. QObject,有一个生存线程(慢慢体会)

     moveToThread本来就是操作QObject的    比如把当前对象移到主线程里: myObject->moveToThread(QApplication::instance()-> ...

  2. Sed常用实例总结

    [Sed简介] sed是一个文件处理工具,本身是一个管道命令,主要用来自动编辑一个或多个文件,简化对文件的反复操作,编写转换程序等.sed以行为单位,一次处理一行内容,处理时,把当前处理的行存储在临时 ...

  3. The parent project must have a packaging type of POM

    在Eclipse中使用Maven添加模块时报错:The parent project must have a packaging type of POM 解决办法: 是将pom.xml 中的  < ...

  4. 《C/C++学习指南》 - 关于本书

    称号 :<C/C++学习指南> 笔者: 邵制成 在线学习(免费),在线答疑 (免费) 创作目的:想以自己的能力和经验为国内(及国外)的读者奉献一本好书,一本让人一看就懂."不可能 ...

  5. ubuntu下使用charles代理

    charles 最新的版本是3.10,但是这个版本还没有license可以用,所以使用3.9.2版本. 解压缩包就可以用了. 如果只是代理http请求,只要设置: Proxy -> Proxy ...

  6. 点击得到QTableWidget中任意位置QPushButton的行列信息

    http://www.qtcn.org/bbs/read-htm-tid-51835.html http://www.qtcn.org/bbs/simple/?t43841.html 比如(点击每行最 ...

  7. 基于visual Studio2013解决C语言竞赛题之1074八皇后

        题目 解决代码及点评 /************************************************************************/ /* ...

  8. Java中怎么控制线程訪问资源的数量

    在API中是这样来描写叙述Semaphore 的 Semaphore 通经常使用于限制能够訪问某些资源(物理或逻辑的)的线程数目. 一个计数信号量.从概念上讲,信号量维护了一个许可集.如有必要,在许可 ...

  9. eclipse之The currrently displayed page contains invalid values错误

    现象: eclipse的preferences里面须要保存密码,保存报错Could Not Accept ChangesThe currrently displayed page contains i ...

  10. ALV前导零的问题

    ALV的IT_FIELDCAT参数中L_ZERO 选项置位的话,对NUM类型的前导0是可以输出的,但是有个很重要的前提条件,NO_ZERO不可以置位,否则L_ZERO是失效的.