PAT 甲级 1027 Colors in Mars (20 分)(简单,进制转换)
People in Mars represent the colors in their computers in a similar way as the Earth people. That is, a color is represented by a 6-digit number, where the first 2 digits are for Red
, the middle 2 digits for Green
, and the last 2 digits for Blue
. The only difference is that they use radix 13 (0-9 and A-C) instead of 16. Now given a color in three decimal numbers (each between 0 and 168), you are supposed to output their Mars RGB values.
Input Specification:
Each input file contains one test case which occupies a line containing the three decimal color values.
Output Specification:
For each test case you should output the Mars RGB value in the following format: first output #
, then followed by a 6-digit number where all the English characters must be upper-cased. If a single color is only 1-digit long, you must print a 0
to its left.
题意:
三个数分别转十三进制
AC代码:
#include <iostream>
using namespace std;
int main(){
char ans[];
for(int i=;i<;i++) ans[i]=i+'';
ans[]='A',ans[]='B',ans[]='C';
int a[];
for(int i=;i<;i++) cin>>a[i];
cout<<"#";
for(int i=;i<;i++){
cout<<ans[a[i]/]<<ans[a[i]%];
}
return ;
}
#include<bits/stdc++.h>
using namespace std;
char d[]={'','','','','','','','','','','A','B','C'};
int main(){
int a[];
cin>>a[]>>a[]>>a[];
cout<<"#";
for(int i=;i<=;i++)
{
int x=a[i];
int b[];
int k=;
//转成13进制
while(x>=){
b[++k] = x/;
x=x%;
}
b[++k]=x;
if(k==){
cout<<<<d[b[]];
}else{
cout<<d[b[]]<<d[b[]];
}
}
return ;
}
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