IntelliJ IDEA 2017版 SpringBoot的Json字符串返回

一、说明

SpringBoot框架已经自动封装好json字符串解析,所以我们只需要用它的注解来返回操作就可以了.

二、实战

1、书写一个实体类User，设置属性id和name

 package com.json;

 /**
  * Created by liuya on 2018-01-17.
  */
 public class UserPoJo
 {
     private int userId;
     private String userName;

     public int getUserId() {
         return userId;
     }

     public void setUserId(int userId) {
         this.userId = userId;
     }

     public String getUserName() {
         return userName;
     }

     public void setUserName(String userName) {
         this.userName = userName;
     }

     @Override
     public String toString() {
         return "UserPoJo{" +
                 "userId=" + userId +
                 ", userName='" + userName + '\'' +
                 '}';
     }
 }

2、书写开启服务器的代码（SpringBoot框架自带一个测试服务器）

 package com.json;

 import org.springframework.boot.SpringApplication;
 import org.springframework.boot.autoconfigure.SpringBootApplication;

 @SpringBootApplication
 public class SpringboothelloApplication {

     public static void main(String[] args) {
         SpringApplication.run(SpringboothelloApplication.class, args);
     }

 }

3、书写controller返回json的代码

 package com.json;

 import org.springframework.web.bind.annotation.RequestMapping;
 import org.springframework.web.bind.annotation.RestController;

 /**
  * Created by liuya on 2018-01-16.
  *
  *  测试用的一个例子
  */

 @RestController
 public class ControllerJson {

     @RequestMapping("user")
     public UserPoJo hello(){
         //实体类赋值
         UserPoJo userPoJo  = new UserPoJo();
         userPoJo.setUserId(111);
         userPoJo.setUserName("王小二");
         //返回实体类
         return userPoJo;
     }
 }

4、启动服务器的代码，生成如图

5、浏览器测试