九度OnlineJudge之1001：A+B for Matrices

题目描述：

This time, you are supposed to find A+B where A and B are two matrices, and then count the number of zero rows and columns.

输入：

The input consists of several test cases, each starts with a pair of positive integers M and N (≤10) which are the number of rows and columns of the matrices, respectively. Then 2*M lines follow, each contains N integers in [-100, 100], separated by a space. The first M lines correspond to the elements of A and the second M lines to that of B.

The input is terminated by a zero M and that case must NOT be processed.

输出：

For each test case you should output in one line the total number of zero rows and columns of A+B.

样例输入：

2 2
1 1
1 1
-1 -1
10 9
2 3
1 2 3
4 5 6
-1 -2 -3
-4 -5 -6
0

样例输出：

1
5

#include <iostream>
#include<string.h>
 
using namespace std;
 
int main()
{
    int A[11][11];
    int B[11][11];
    int C[11][11];
 
    int M,N;
    int i,j;
    while(cin>>M>>N,M!=0)
    {
     int k =0;
    memset(A,0,sizeof(A));
    memset(B,0,sizeof(B));
    memset(C,0,sizeof(C));    
 
      for(i=0;i<M;i++)
       for(j=0;j<N;j++)
          cin>>A[i][j];
 
     for(i=0;i<M;i++)
       for(j=0;j<N;j++)
          cin>>B[i][j]; 
 
     for(i=0;i<M;i++)
       for(j=0;j<N;j++)
         C[i][j]=A[i][j]+B[i][j]; 
 
     for(i=0;i<N;i++)
  {
     for(j=0;j<M;j++)
     {
        if(C[j][i] != 0)
        break;
     }
     if(j==M) k++;
 
  }
    for(j=0;j<M;j++)
    {
       for(i=0;i<N;i++)
     {
        if(C[j][i] != 0)
        break;
     }
     if(i==N) k++;
  }
    cout<<k<<endl;    
 
    }
 
   // system("PAUSE");
    return 0;
}