HDOJ 1019 Least Common Multiple(最小公倍数问题)

Problem Description

The least common multiple (LCM) of a set of positive integers is the smallest positive integer which is divisible by all the numbers in the set. For example, the LCM of 5, 7 and 15 is 105.

Input

Input will consist of multiple problem instances. The first line of the input will contain a single integer indicating the number of problem instances. Each instance will consist of a single line of the form m n1 n2 n3 … nm where m is the number of integers in the set and n1 … nm are the integers. All integers will be positive and lie within the range of a 32-bit integer.

Output

For each problem instance, output a single line containing the corresponding LCM. All results will lie in the range of a 32-bit integer.

Sample Input

2

3 5 7 15

6 4 10296 936 1287 792 1

Sample Output

105

10296

import java.util.Scanner;

public class Main {
    public static void main(String[] args) {
        Scanner sc = new Scanner(System.in);
        int t = sc.nextInt();
        while(t-->0){
            int n = sc.nextInt();
            int a[] = new int[n];
            for(int i=0;i<n;i++){
                a[i] = sc.nextInt();
            }
            int k = a[0];
            for(int i=1;i<n;i++){
                int b = a[i];
                if(k>b){
                    b=b^k;
                    k=b^k;
                    b=b^k;
                }
                k=su(b,k,mod(b,k));
            }

            System.out.println(k);

        }
    }

    //最小公倍数。
    private static int su(int b, int k, int mod) {
        return k*(b/mod);
    }

    //求最大公约数，辗转相除法。b>k
    private static int mod(int b, int k) {
        while(k>0){
            int m = b%k;
            b=k;
            k=m;
        }
        return b;
    }
}