Distinct Substrings SPOJ - DISUBSTR(后缀数组水题)

求不重复的子串个数

用所有的减去height就好了 推出来的。。。

#include <iostream>
#include <cstdio>
#include <sstream>
#include <cstring>
#include <map>
#include <cctype>
#include <set>
#include <vector>
#include <stack>
#include <queue>
#include <algorithm>
#include <cmath>
#define rap(i, a, n) for(int i=a; i<=n; i++)
#define rep(i, a, n) for(int i=a; i<n; i++)
#define lap(i, a, n) for(int i=n; i>=a; i--)
#define lep(i, a, n) for(int i=n; i>a; i--)
#define rd(a) scanf("%d", &a)
#define rlld(a) scanf("%lld", &a)
#define rc(a) scanf("%c", &a)
#define rs(a) scanf("%s", a)
#define MOD 2018
#define LL long long
#define ULL unsigned long long
#define Pair pair<int, int>
#define mem(a, b) memset(a, b, sizeof(a))
#define _  ios_base::sync_with_stdio(0),cin.tie(0)
//freopen("1.txt", "r", stdin);
using namespace std;
const int maxn = , INF = 0x7fffffff;
 
char a[maxn];
int s[maxn];
int sa[maxn], t[maxn], t2[maxn], c[maxn], n;
int ran[maxn], height[maxn];
 
void get_sa(int m)
{
    int i, *x = t, *y = t2;
    for(i = ; i < m; i++) c[i] = ;
    for(i = ; i < n; i++) c[x[i] = s[i]]++;
    for(i = ; i < m; i++) c[i] += c[i-];
    for(i = n-; i >= ; i--) sa[--c[x[i]]] = i;
    for(int k = ; k <= n; k <<= )
    {
        int p = ;
        for(i = n-k; i < n; i++) y[p++] = i;
        for(i = ; i < n; i++) if(sa[i] >= k) y[p++] = sa[i] - k;
        for(i = ; i < m; i++) c[i] = ;
        for(i = ; i < n; i++) c[x[y[i]]]++;
        for(i = ; i< m; i++) c[i] += c[i-];
        for(i = n-; i >= ; i--) sa[--c[x[y[i]]]] = y[i];
        swap(x, y);
        p = ; x[sa[]] = ;
        for(i = ; i < n; i++)
            x[sa[i]] = y[sa[i-]] == y[sa[i]] && y[sa[i-]+k] == y[sa[i]+k] ? p- : p++;
        if(p >= n) break;
        m = p;
    }
    int k = ;
    for(i = ; i < n; i++) ran[sa[i]] = i;
    for(i = ; i < n; i++)
    {
        if(k) k--;
        int j = sa[ran[i]-];
        while(s[i+k] == s[j+k]) k++;
        height[ran[i]] = k;
    }
}
 
int main()
{
    int T;
    rd(T);
    while(T--)
    {
        rs(a);
        n = strlen(a);
        rep(i, , n)
            s[i] = a[i];
        int sum = n*(n+)/;
        s[n++] = ;
        get_sa();
        rep(i, , n)
            sum -= height[i];
        cout<< sum <<endl;
 
    }
 
    return ;
}