一. 题目
I Think I Need a Houseboat
Time Limit: 1000MS   Memory Limit: 10000K
Total Submissions: 97512   Accepted: 42430

Description

Fred Mapper is considering purchasing some land in Louisiana to build his house on. In the process of investigating the land, he learned that the state of Louisiana is actually shrinking by 50 square miles each year, due to erosion caused by the Mississippi River. Since Fred is hoping to live in this house the rest of his life, he needs to know if his land is going to be lost to erosion.

After doing more research, Fred has learned that the land that is
being lost forms a semicircle. This semicircle is part of a circle
centered at (0,0), with the line that bisects the circle being the X
axis. Locations below the X axis are in the water. The semicircle has an
area of 0 at the beginning of year 1. (Semicircle illustrated in the
Figure.)

Input

The
first line of input will be a positive integer indicating how many data
sets will be included (N). Each of the next N lines will contain the X
and Y Cartesian coordinates of the land Fred is considering. These will
be floating point numbers measured in miles. The Y coordinate will be
non-negative. (0,0) will not be given.

Output

For
each data set, a single line of output should appear. This line should
take the form of: “Property N: This property will begin eroding in year
Z.” Where N is the data set (counting from 1), and Z is the first year
(start from 1) this property will be within the semicircle AT THE END OF
YEAR Z. Z must be an integer. After the last data set, this should
print out “END OF OUTPUT.”

Sample Input

2
1.0 1.0
25.0 0.0

Sample Output

Property 1: This property will begin eroding in year 1.
Property 2: This property will begin eroding in year 20.
END OF OUTPUT.

Hint

1.No property will appear exactly on the semicircle boundary: it will either be inside or outside.
2.This problem will be judged automatically. Your answer must match
exactly, including the capitalization, punctuation, and white-space.
This includes the periods at the ends of the lines.

3.All locations are given in miles.

Source

二. 题意
  • 河水以每年50平方为单位,呈半圆形扩张侵蚀土地
  • 以半圆中心点(0, 0), 建立坐标系
  • 给出坐标(x, y),输出该点土地在哪一年会被侵蚀

三. 分析

  • 算法核心: 题目较为简单,只需知道基本的求圆面积的几何公式
  • 实现细节:
    • 圆面积公式
    • 结果输出的条件判断
    • 浮点类型运算

四. 题解

 #include <stdio.h>
#define PI 3.1415927 int main()
{
int area, year, i, count;
float x, y; scanf("%d\n", &count);
for (i = ; i <= count; i++) {
scanf("%f %f\n", &x, &y); area = ; year = ;
while () {
area += ;
if (area > (PI * (x * x + y * y) / )) break;
year++;
}
printf("Property %d: This property will begin eroding in year %ld.\n", i, year);
} printf("END OF OUTPUT.\n");
return ;
}

[POJ] #1005# I Think I Need a Houseboat : 浮点数运算的更多相关文章

  1. POJ. 1005 I Think I Need a Houseboat(水 )

    POJ. 1005 I Think I Need a Houseboat(水 ) 代码总览 #include <cstdio> #include <cstring> #incl ...

  2. OpenJudge/Poj 1005 I Think I Need a Houseboat

    1.链接地址: http://bailian.openjudge.cn/practice/1005/ http://poj.org/problem?id=1005 2.题目: I Think I Ne ...

  3. [POJ 1005] I Think I Need a Houseboat C++解题

        I Think I Need a Houseboat Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 81874   ...

  4. poj 1005:I Think I Need a Houseboat(水题,模拟)

    I Think I Need a Houseboat Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 85149   Acce ...

  5. poj 1005 I Think I Need a Houseboat

    #include <iostream> using namespace std; const double pi = 3.1415926535; int main() { ;; doubl ...

  6. I Think I Need a Houseboat POJ - 1005

    I Think I Need a Houseboat POJ - 1005 解题思路:水题 #include <iostream> #include <cstdio> #inc ...

  7. I Think I Need a Houseboat POJ - 1005(数学)

    题目大意 在二维坐标内选定一个点,问你当洪水以半圆形扩散且每年扩散50单位,哪一年这个点被被洪水侵蚀? 解法 代码 #include <iostream> #include <cst ...

  8. POJ 1005 解题报告

    1.题目描述   2.解题思路 好吧,这是个水题,我的目的暂时是把poj第一页刷之,所以水题也写写吧,这个题简单数学常识而已,给定坐标(x,y),易知当圆心为(0,0)时,半圆面积为0.5*PI*(x ...

  9. 1005 -- I Think I Need a Houseboat

    I Think I Need a Houseboat Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 105186   Acc ...

随机推荐

  1. Java面试汇总

    转自:http://zy19982004.iteye.com/blog/1846537#comments 一.All 最近找工作,遇到的笔试面试题,归纳如下,供大家参考. 二.J2SE 容器 Hash ...

  2. hdu - 1829 A Bug's Life (并查集)&&poj - 2492 A Bug's Life && poj 1703 Find them, Catch them

    http://acm.hdu.edu.cn/showproblem.php?pid=1829 http://poj.org/problem?id=2492 臭虫有两种性别,并且只有异性相吸,给定n条臭 ...

  3. 第7篇 ORACLE EBS DEMO虚拟机环境的安装

    ERP信息系统的实施不仅要求懂得道理方面的知识,更要侧重于应用实践.为了有一个稳定的测试环境.初学者可以自己搭建一个EBS DEMO环境.本节介绍EBS DEMO环境虚拟机的安装.一. 安装前的准备( ...

  4. 修改tomcat小猫图标

    网站放到网上去了,不喜欢大家访问的时候可以看到tomcat的小猫图标.今天在网上搜了搜,总结一下收藏了. 1.直接找个16*16的ico图片.放到tomcat/root下,取个名叫favicon.ic ...

  5. 使用Jenkins构建持续集成环境

    简介 Jenkins是一个开源的持续集成工具,提供了数百种插件供用户选择,能够完成整套持续集成环境的构建. 它具有如下的特点: 持续集成和持续发布 作为可扩展的自动服务器,Jenkins可以作为简单的 ...

  6. UVa 12206 (字符串哈希) Stammering Aliens

    体验了一把字符串Hash的做法,感觉Hash这种人品算法好神奇. 也许这道题的正解是后缀数组,但Hash做法的优势就是编码复杂度大大降低. #include <cstdio> #inclu ...

  7. 漫游Kafka实现篇之消息和日志

    消息格式 消息由一个固定长度的头部和可变长度的字节数组组成.头部包含了一个版本号和CRC32校验码. /** * 具有N个字节的消息的格式如下 * * 如果版本号是0 * * 1. 1个字节的 &qu ...

  8. 韦东山驱动视频笔记——3.字符设备驱动程序之poll机制

    linux内核版本:linux-2.6.30.4 目的:我们在中断方式的按键应用程序中,如果没有按键按下,read就会永远在那等待,所以如果在这个程序里还想做其他事就不可能了.因此我们这次改进它,让它 ...

  9. 20160204.CCPP体系详解(0014天)

    程序片段(01):define.h+data.h&data.c+control.h&control.c+view.h&view.c+AI.h&AI.c+main.c 内 ...

  10. tornado 实践 - 目录结构

    . ├── README.md └── store_management ├── Session.vim ├── auth │   ├── __init__.py │   ├── views.py ├ ...