Codeforces Beta Round #77 (Div. 2 Only) A. Football【字符串/判断是否存在连续7个0或7个1】
2 seconds
256 megabytes
standard input
standard output
Petya loves football very much. One day, as he was watching a football match, he was writing the players' current positions on a piece of paper. To simplify the situation he depicted it as a string consisting of zeroes and ones. A zero corresponds to players of one team; a one corresponds to players of another team. If there are at least 7 players of some team standing one after another, then the situation is considered dangerous. For example, the situation 00100110111111101 is dangerous and11110111011101 is not. You are given the current situation. Determine whether it is dangerous or not.
The first input line contains a non-empty string consisting of characters "0" and "1", which represents players. The length of the string does not exceed 100 characters. There's at least one player from each team present on the field.
Print "YES" if the situation is dangerous. Otherwise, print "NO".
001001
NO
1000000001
YES 【代码】:
#include <bits/stdc++.h> using namespace std;
int cnt=1;
int main ()
{
string a;
cin>>a;
for(int i=0;i<a.size();i++)
{
if(a.find("0000000")!= a.npos||a.find("1111111")!= a.npos)
{
puts("YES");
return 0;
}
}
puts("NO");
return 0;
}
Codeforces Beta Round #77 (Div. 2 Only) A. Football【字符串/判断是否存在连续7个0或7个1】的更多相关文章
- codeforces水题100道 第二十三题 Codeforces Beta Round #77 (Div. 2 Only) A. Football (strings)
题目链接:http://www.codeforces.com/problemset/problem/96/A题意:判断一个0-1字符串中出现的最长的0字串或者1字串的长度是否大于等于7.C++代码: ...
- Codeforces Beta Round #77 (Div. 2 Only)
Codeforces Beta Round #77 (Div. 2 Only) http://codeforces.com/contest/96 A #include<bits/stdc++.h ...
- Codeforces Beta Round #77 (Div. 1 Only) C. Volleyball (最短路)
题目链接:http://codeforces.com/contest/95/problem/C 思路:首先dijkstra预处理出每个顶点到其他顶点的最短距离,然后如果该出租车到某个顶点的距离小于等于 ...
- Codeforces Beta Round #80 (Div. 2 Only)【ABCD】
Codeforces Beta Round #80 (Div. 2 Only) A Blackjack1 题意 一共52张扑克,A代表1或者11,2-10表示自己的数字,其他都表示10 现在你已经有一 ...
- Codeforces Beta Round #83 (Div. 1 Only)题解【ABCD】
Codeforces Beta Round #83 (Div. 1 Only) A. Dorm Water Supply 题意 给你一个n点m边的图,保证每个点的入度和出度最多为1 如果这个点入度为0 ...
- Codeforces Beta Round #79 (Div. 2 Only)
Codeforces Beta Round #79 (Div. 2 Only) http://codeforces.com/contest/102 A #include<bits/stdc++. ...
- Codeforces Beta Round #76 (Div. 2 Only)
Codeforces Beta Round #76 (Div. 2 Only) http://codeforces.com/contest/94 A #include<bits/stdc++.h ...
- Codeforces Beta Round #75 (Div. 2 Only)
Codeforces Beta Round #75 (Div. 2 Only) http://codeforces.com/contest/92 A #include<iostream> ...
- Codeforces Beta Round #74 (Div. 2 Only)
Codeforces Beta Round #74 (Div. 2 Only) http://codeforces.com/contest/90 A #include<iostream> ...
随机推荐
- 封装了一个HOOKAPI的类。。。
我惊奇地发现,我手竟然这么生了..... 很久很久没有写这方面的东西,现在写着竟然这么手生....哎.... 这玩艺,还得天天练....
- 转载:Linux 安装Java
1.到官网下载 jdk-8u131-linux-x64.tar.gz 官网地址:http://www.Oracle.com/technetwork/java/javase/downloads/jdk8 ...
- 使用springboot上传文件至nginx代理服务器
nginx配置图片服务器 server { listen 8001; server_name image.xxx.com; proxy_set_header X-Forwarded-Host $hos ...
- 第一个WindowService服务
背景:Web项目中需要定时执行一段程序 方法: 1.新建一个WindowService项目 2.添加代码 public partial class Service1 : ServiceBase { S ...
- SQLServer 2008 的数据库日志清理
-- SQLServer 2008 的数据库日志清理 ,与 Sql2000 或 2005 的方法不一样,需要采用 下面的sql来清理 USE [master] GO ALTER DATABASE [数 ...
- Lombock原理
说道Lombok,可能会鲜为人知.但是在实际的开发中,它起到了很大的作用,话不多说,直入正题: 一.Lombok是什么 现在看一下Lombok官方对其进行的解释:Lombok官网:https://pr ...
- 一条sql获取每个类别最新的一条记录
1.初始化数据 create table Products ( id ,), name ), categroy int, addtime datetime , ) insert into Produc ...
- [C#] 生成 (web): 未能加载文件或程序集“Microsoft.CSharp, Version=4.0.0.0, Culture=neutral, PublicKeyToken=b03f5f7
有时候编译asp.net会遇到奇怪的错误: 生成 (web): 未能加载文件或程序集"Microsoft.CSharp, Version=4.0.0.0, Culture=neutral, ...
- 【Redis安装】部署与基本配置 --基于Mac和Linux
Redis安装与部署[基于Mac和Linux] 一.Redis简介 基于内存的Key-Value高性能NoSQL数据库 二.Redis下载和解压 进入官网下载最新版的Redis,目前是5.0.0,这个 ...
- PAT甲级——A1045 Favorite Color Stripe
Eva is trying to make her own color stripe out of a given one. She would like to keep only her favor ...