[PAT] 1147 Heaps(30 分)
1147 Heaps(30 分)
In computer science, a heap is a specialized tree-based data structure that satisfies the heap property: if P is a parent node of C, then the key (the value) of P is either greater than or equal to (in a max heap) or less than or equal to (in a min heap) the key of C. A common implementation of a heap is the binary heap, in which the tree is a complete binary tree. (Quoted from Wikipedia at https://en.wikipedia.org/wiki/Heap_(data_structure)
Your job is to tell if a given complete binary tree is a heap.
Input Specification:
Each input file contains one test case. For each case, the first line gives two positive integers: M (≤ 100), the number of trees to be tested; and N (1 < N ≤ 1,000), the number of keys in each tree, respectively. Then M lines follow, each contains N distinct integer keys (all in the range of int), which gives the level order traversal sequence of a complete binary tree.
Output Specification:
For each given tree, print in a line Max Heap
if it is a max heap, or Min Heap
for a min heap, or Not Heap
if it is not a heap at all. Then in the next line print the tree's postorder traversal sequence. All the numbers are separated by a space, and there must no extra space at the beginning or the end of the line.
Sample Input:
3 8
98 72 86 60 65 12 23 50
8 38 25 58 52 82 70 60
10 28 15 12 34 9 8 56
Sample Output:
Max Heap
50 60 65 72 12 23 86 98
Min Heap
60 58 52 38 82 70 25 8
Not Heap
56 12 34 28 9 8 15 10
题意:
给定层序遍历的树,判断是否为大小堆。
思路:
先将输出转化为一棵树,这样就好做了,就是比较暴力
看看 柳婼 の blog 是怎么做的
题解:
#include<cstdlib> #include<cstdio> #include<vector> using namespace std; struct node { int value; int left; int right; }; bool isMaxHeap(vector<node> nodes, int now) { bool isMax = true; < nodes.size()) { ].value) { isMax = false; } else { )) { isMax = false; } } } + < nodes.size()) { + ].value) { isMax = false; } else { + )) { isMax = false; } } } return isMax; } bool isMinHeap(vector<node> nodes, int now) { bool isMin = true; < nodes.size()) { ].value) { isMin = false; } else { )) { isMin = false; } } } + < nodes.size()) { + ].value) { isMin = false; } else { + )) { isMin = false; } } } return isMin; } void PostOrder(vector<node> nodes, int now) { < nodes.size()) { PostOrder(nodes, now * ); } + < nodes.size()) { PostOrder(nodes, now * + ); } //nodes[nodes.size() - 1]这个结点不一定是先输出的。 printf( ? "\n" : " "); } int main() { int n, m; scanf("%d %d", &n, &m); ; i < n; i++) { vector<node> nodes(m+); ; j <= m; j++) { scanf("%d", &nodes[j].value); nodes[j].left = j * ; nodes[j].right = j * + ; } )) { printf("Max Heap\n"); } )) { printf("Min Heap\n"); } else { printf("Not Heap\n"); } PostOrder(nodes, ); } ; }
[PAT] 1147 Heaps(30 分)的更多相关文章
- PAT 甲级 1147 Heaps (30 分) (层序遍历,如何建树,后序输出,还有更简单的方法~)
1147 Heaps (30 分) In computer science, a heap is a specialized tree-based data structure that sati ...
- PAT 1147 Heaps[难]
1147 Heaps(30 分) In computer science, a heap is a specialized tree-based data structure that satisfi ...
- PAT Advanced 1147 Heaps (30) [堆,树的遍历]
题目 In computer science, a heap is a specialized tree-based data structure that satisfies the heap pr ...
- PAT 1147 Heaps
https://pintia.cn/problem-sets/994805342720868352/problems/994805342821531648 In computer science, a ...
- 1147. Heaps (30)
In computer science, a heap is a specialized tree-based data structure that satisfies the heap prope ...
- PAT甲级:1064 Complete Binary Search Tree (30分)
PAT甲级:1064 Complete Binary Search Tree (30分) 题干 A Binary Search Tree (BST) is recursively defined as ...
- PAT A1127 ZigZagging on a Tree (30 分)——二叉树,建树,层序遍历
Suppose that all the keys in a binary tree are distinct positive integers. A unique binary tree can ...
- 【PAT】1053 Path of Equal Weight(30 分)
1053 Path of Equal Weight(30 分) Given a non-empty tree with root R, and with weight Wi assigned t ...
- 【PAT】1091 Acute Stroke(30 分)
1091 Acute Stroke(30 分) One important factor to identify acute stroke (急性脑卒中) is the volume of the s ...
随机推荐
- HDU4825:Xor Sum——题解
http://acm.hdu.edu.cn/showproblem.php?pid=4825 Zeus 和 Prometheus 做了一个游戏,Prometheus 给 Zeus 一个集合,集合中包含 ...
- 洛谷 P2898 [USACO08JAN]haybale猜测Haybale Guessing 解题报告
[USACO08JAN]haybale猜测Haybale Guessing 题目描述 给一段长度为\(n\),每个位置上的数都不同的序列\(a[1\dots n]\)和\(q\)和问答,每个问答是\( ...
- [CEOI2017]Mousetrap
P4654 [CEOI2017]Mousetrap 博弈论既视感 身临其境感受耗子和管理的心理历程. 以陷阱为根考虑.就要把耗子赶到根部. 首先一定有解. 作为耗子,为了拖延时间,必然会找到一个子树往 ...
- 内存和cpu
http://www.blogjava.net/fjzag/articles/317773.html ubuntu@ubuntu-vm:/work/sv-g5-application/projects ...
- Oracle内存全面分析
Oracle内存全面分析 Oracle的内存配置与oracle性能息息相关.而且关于内存的错误(如4030.4031错误)都是十分令人头疼的问题.可以说,关于内存的配置,是最影响Oracle性能的配置 ...
- C#中excel读取和写入
1.方法一:采用OleDB读取EXCEL文件: 把EXCEL文件当做一个数据源来进行数据的读取操作,实例如下: public DataSet ExcelToDS(string Path) { stri ...
- sublime 常用插件 感觉比较全了 够用了
插件介绍 Package Control 功能:安装包管理 简介:sublime插件控制台,提供添加.删除.禁用.查找插件等功能 使用:https://sublime.wbond.net/instal ...
- python基础---输入输出
1.输入字符串. name=input() or name=input('please input a string') 这样可以接收一个字符串,包括空格,都可以输入.只有回车不接受,作为结束符, ...
- [洛谷P2375] [NOI2014]动物园
洛谷题目链接:[NOI2014]动物园 题目描述 近日,园长发现动物园中好吃懒做的动物越来越多了.例如企鹅,只会卖萌向游客要吃的.为了整治动物园的不良风气,让动物们凭自己的真才实学向游客要吃的,园长决 ...
- python内置函数lambda、filter、map、reduce
lambda匿名函数 1.lambda只是一个表达式,函数体比def简单多. 2.lambda的主体是一个表达式,而不是一个代码块.仅仅能在lambda表达式中封装有限的逻辑进去 3.lambda函数 ...