下面的分桶个数做的不太好,原来的解法是用的

int gap = (big - small) / vlen;
if (gap == 0) {
gap = 1;
}

下面是现在的Java解法:

package com.company;

import java.util.*;

class Solution {
public int maximumGap(int[] nums) {
if (nums.length < 2) {
return 0;
} // 用 Radix 排序
int small = Integer.MAX_VALUE;
int big = 0;
for (int num : nums) {
if (num < small) {
small = num;
}
if (num > big) {
big = num;
}
}
System.out.println("big is " + big + " small " + small);
int gap = (big - small - 1) / (nums.length - 1) + 1;
if (gap == 0) {
return 0;
}
int gap_num = (big - small) / gap + 1;
int[] first = new int[gap_num];
int[] second = new int[gap_num];
// [ )
System.out.println("gap is " + gap + " len is " + nums.length + "big is " + big + " small " + small);
for (int num : nums) {
int index = (num - small) / gap;
if (first[index] == 0 || num < first[index]) {
first[index] = num;
}
if (second[index] == 0 || num > second[index]) {
second[index] = num;
}
}
int ret = -1;
int last = -1;
for (int i=0; i<gap_num; i++) {
if (first[i] == 0) {
continue;
}
if (last == -1) {
last = second[i];
ret = last - first[i];
}
else {
if (first[i] - last > ret) {
ret = first[i] - last;
}
if (second[i] - first[i] > ret) {
ret = second[i] - first[i];
}
last = second[i];
} }
return ret;
}
} public class Main { public static void main(String[] args) {
System.out.println("Hello!");
Solution solution = new Solution(); int[] nums = {1,1,1,1,1,5,5,5,5,5}; int ret = solution.maximumGap(nums);
System.out.printf("Get ret: %s\n", ret); /*Iterator<List<Integer>> iterator = ret.iterator();
while (iterator.hasNext()) {
Iterator iter = iterator.next().iterator();
while (iter.hasNext()) {
System.out.printf("%d,", iter.next());
}
System.out.println();
}*/ System.out.println(); }
}

maximum-gap(经过了提示)的更多相关文章

  1. 【leetcode】Maximum Gap

    Maximum Gap Given an unsorted array, find the maximum difference between the successive elements in ...

  2. [LintCode] Maximum Gap 求最大间距

    Given an unsorted array, find the maximum difference between the successive elements in its sorted f ...

  3. 线性时间的排序算法--桶排序(以leetcode164. Maximum Gap为例讲解)

    前言 在比较排序的算法中,快速排序的性能最佳,时间复杂度是O(N*logN).因此,在使用比较排序时,时间复杂度的下限就是O(N*logN).而桶排序的时间复杂度是O(N+C),因为它的实现并不是基于 ...

  4. Maximum Gap

    Given an unsorted array, find the maximum difference between the successive elements in its sorted f ...

  5. leetcode[164] Maximum Gap

    梅西刚梅开二度,我也记一题. 在一个没排序的数组里,找出排序后的相邻数字的最大差值. 要求用线性时间和空间. 如果用nlgn的话,直接排序然后判断就可以了.so easy class Solution ...

  6. 【leetcode 桶排序】Maximum Gap

    1.题目 Given an unsorted array, find the maximum difference between the successive elements in its sor ...

  7. 【LeetCode】164. Maximum Gap (2 solutions)

    Maximum Gap Given an unsorted array, find the maximum difference between the successive elements in ...

  8. 由Maximum Gap,对话桶排序,基数排序和统计排序

    一些非比较排序 在LeetCode中有个题目叫Maximum Gap.是求一个非排序的正数数列中按顺序排列后的最大间隔.这个题用桶排序和基数排序都能够实现.以下说一下桶排序.基数排序和计数排序这三种非 ...

  9. LeetCode 164. Maximum Gap[翻译]

    164. Maximum Gap 164. 最大间隔 Given an unsorted array, find the maximum difference between the successi ...

  10. 【刷题-LeetCode】164 Maximum Gap

    Maximum Gap Given an unsorted array, find the maximum difference between the successive elements in ...

随机推荐

  1. nodejs redis

    0. install redis library for node npm install redis 1.node command example > var _redis = require ...

  2. 复习linq

    复习linq linq的英文是language integrated query.其中query的意思就是疑问或者计算机用语就是从资料库中提取信息的要求,可以理解为查询的意思.那么它翻译过来的话就是集 ...

  3. android 开发不能创建目录

    原来代码: File tempDir = new File(path); //path 是一个参数 if (!tempDir.exists()) { try { tempDir.mkdir(); // ...

  4. SQLServer 语句-创建索引【转】

    语法:CREATE [索引类型] INDEX 索引名称ON 表名(列名)WITH FILLFACTOR = 填充因子值0~100GO /*实例*/USE 库名GOIF EXISTS (SELECT * ...

  5. hadoop历史服务器配置问题

    作者:sdjnzqr 出处:http://www.cnblogs.com/sdjnzqr/ 版权:本文版权归作者和博客园共有 转载:欢迎转载,但未经作者同意,必须保留此段声明:必须在文章中给出原文连接 ...

  6. asynDBCenter(修改)

    asynDBCenter加入数据库心跳,其实是没有找到更好的方法,看看和以前有什么不同 mongo数据库重练,暂时没有找到好办法,只能这样定时访问 bool asynDBCenter::init(bo ...

  7. 为什么乱码:<meta http-equiv="content-type">前的非ANSI字符

    为什么乱码:<meta http-equiv="content-type">前的非ANSI字符 浏览器检测网页字符集的默认顺序 浏览器的网页字符集检测顺序通常是: ch ...

  8. POJ 3421

    X-factor Chains Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 5111   Accepted: 1622 D ...

  9. IOS 视图控制对象生命周期-init、viewDidLoad、viewWillAppear、viewDidAppear、viewWillDisappear等的区别及用途

    iOS视图控制对象生命周期-init.viewDidLoad.viewWillAppear.viewDidAppear.viewWillDisappear.viewDidDisappear的区别及用途 ...

  10. 使用git代替FTP部署代码到服务器的例子

    这篇文章主要介绍了使用git代替FTP部署代码到服务器的例子,这种方法可以节省流量.节省时间,需要的朋友可以参考下 本地开发完成后,通常会在服务器上部署,有人会使用ftp,有人会使用scp, ftp和 ...