（数论）LightOJ -- 1245

http://acm.hust.edu.cn/vjudge/contest/view.action?cid=98634#problem/B（acm14）

Description

I was trying to solve problem '1234 - Harmonic Number', I wrote the following code

long long H( int n ) {
    long long res = 0;
    for( int i = 1; i <= n; i++ )
        res = res + n / i;
    return res;
}

Yes, my error was that I was using the integer divisions only. However, you are given n, you have to find H(n) as in my code.

Input

Input starts with an integer T (≤ 1000), denoting the number of test cases.

Each case starts with a line containing an integer n (1 ≤ n < 2³¹).

Output

For each case, print the case number and H(n) calculated by the code.

Sample Input

11

1

2

3

4

5

6

7

8

9

10

2147483647

Sample Output

Case 1: 1

Case 2: 3

Case 3: 5

Case 4: 8

Case 5: 10

Case 6: 14

Case 7: 16

Case 8: 20

Case 9: 23

Case 10: 27

Case 11: 46475828386

#include <iostream>
#include <cstdio>
#include <cstring>
#include <cstdlib>
#include <cmath>
#include <algorithm>
#include <map>
 
using namespace std;
 
#define N 200005
 
int main()
{
    long long T, iCase=;
 
    scanf("%d", &T);
 
    while(T--)
    {
        long long n, i;
 
        scanf("%lld", &n);
 
        long long a, num = , sum = n, pre=n;
 
        for(i=; i<=n; i++)
        {
            a = n/i;
            num += (pre-a);
            sum += (pre-a)*(i-);
 
            if(num==n)
                break;
 
            num++;
            sum += a;
            if(num==n)
                break;
 
            pre = a;
        }
 
        printf("Case %lld: %lld\n", iCase++, sum);
    }
 
    return ;
}