Follow up for "Unique Paths":

Now consider if some obstacles are added to the grids. How many unique paths would there be?

An obstacle and empty space is marked as 1 and 0 respectively in the grid.

For example,

There is one obstacle in the middle of a 3x3 grid as illustrated below.

[
[0,0,0],
[0,1,0],
[0,0,0]
] he total number of unique paths is 2. Note: m and n will be at most 100.

  同Unique Paths的DP类似。

class Solution {
public:
int uniquePathsWithObstacles(vector<vector<int> > &obstacleGrid) {
// Start typing your C/C++ solution below
// DO NOT write int main() function
int m = obstacleGrid.size();
int n = obstacleGrid[].size();
vector<vector<int>> grid(m, vector<int>(n,));
for(int i = ; i< n; i++)
if(obstacleGrid[][i] ==) grid[][i] = ;
else break;
for(int i = ; i< m; i++)
if(obstacleGrid[i][] == ) grid[i][] = ;
else break; for(int i = ; i< m; i++)
for(int j = ; j< n; j++)
if(obstacleGrid[i][j] == )
grid[i][j] = grid[i-][j] + grid[i][j-]; return grid[m-][n-];
}
};

LeetCode_Unique Paths II的更多相关文章

  1. LEETCODE —— Unique Paths II [动态规划 Dynamic Programming]

    唯一路径问题II Unique Paths II Follow up for "Unique Paths": Now consider if some obstacles are ...

  2. 62. Unique Paths && 63 Unique Paths II

    https://leetcode.com/problems/unique-paths/ 这道题,不利用动态规划基本上规模变大会运行超时,下面自己写得这段代码,直接暴力破解,只能应付小规模的情形,当23 ...

  3. 【leetcode】Unique Paths II

    Unique Paths II Total Accepted: 22828 Total Submissions: 81414My Submissions Follow up for "Uni ...

  4. 61. Unique Paths && Unique Paths II

    Unique Paths A robot is located at the top-left corner of a m x n grid (marked 'Start' in the diagra ...

  5. LeetCode: Unique Paths II 解题报告

    Unique Paths II Total Accepted: 31019 Total Submissions: 110866My Submissions Question Solution  Fol ...

  6. 【LeetCode练习题】Unique Paths II

    Unique Paths II Follow up for "Unique Paths": Now consider if some obstacles are added to ...

  7. LeetCode之“动态规划”:Minimum Path Sum && Unique Paths && Unique Paths II

    之所以将这三道题放在一起,是因为这三道题非常类似. 1. Minimum Path Sum 题目链接 题目要求: Given a m x n grid filled with non-negative ...

  8. [LeetCode] Unique Paths && Unique Paths II && Minimum Path Sum (动态规划之 Matrix DP )

    Unique Paths https://oj.leetcode.com/problems/unique-paths/ A robot is located at the top-left corne ...

  9. LEETCODE —— Unique Paths II [Dynamic Programming]

    唯一路径问题II Unique Paths II Follow up for "Unique Paths": Now consider if some obstacles are ...

随机推荐

  1. C++中的string类(1)

    http://blog.sina.com.cn/s/blog_51409e8f01009h7g.html 前言: string 的角色1 string 使用1.1 充分使用string 操作符1.2 ...

  2. SpringMVC 拦截器(interceptors)对样式(css),JavaScript(js),图片(images)链接的拦截

    因为在web.xml配置了 <servlet-mapping> <servlet-name>appServlet</servlet-name> <url-pa ...

  3. 简单的新闻客户端APP开发(DCloud+thinkphp+scrapy)

    前端时间花了1个月左右,搞了个新闻APP,功能很简单,就是把页面版的新闻条目定时爬到后台数据库,然后用app显示出来. 1.客户端 使用了DCloud框架,js基本是个新手,从没写过像样的代码,htm ...

  4. s16_day01

    一.基础 1.编码 ascii-->GB2312-->GB18030-->GBK-->unicode-->UTF8可变长 2.数据类型 int,long,float,co ...

  5. js的意义,引用方法及变量

    一 JavaScript的意义. Javascript是浏览器端的脚本语言,它能够访问web页面的元素和运行它得浏览器,从而可以操作元素,创建新的元素等.它主要的作用有: 1.以指定尺寸.位置和样式( ...

  6. 全文搜索-介绍-elasticsearch-definitive-guide翻译

    全文搜索 我们通过前文的简单样例,已经了解了结构化数据的条件搜索:如今.让我们来了解全文搜索-- 如何通过匹配全部域的文本找到最相关的文章. 关于全文搜索有两个最重要的方面: 相似度计算 通过TF/I ...

  7. Android -------- RelativeLayout 和 LinearLayout 的性能分析

    布局的绘制角度 RelativeLayout不如LinearLayout快的根本原因是: RelativeLayout需要对其子View进行两次measure过程, 而LinearLayout则只需一 ...

  8. .NET Linq获取一个集合中的一个或多个属性,赋值到新的类对象

    //得到自定义的list var list = schoolGradeClassModelList.Select(x => new DropDownListData() { DataTextFi ...

  9. iOS_SN_地图的使用(3)

    地图的定位,记得不用定位的时候要关掉定位不然会一直定位,使电量使用过快. - (void)viewDidLoad { [super viewDidLoad]; // Do any additional ...

  10. zepto源码研究 - deferred.js(jquery-deferred.js)

    简要:zepto的deferred.js 并不遵守promise/A+ 规范,而在jquery v3.0.0中的defer在一定程度上实现了promise/A+ ,因此本文主要研究jquery v3. ...