I - u Calculate e
Description
where n is allowed to go to infinity. This can actually yield very accurate approximations of e using relatively small values of n.
Output
Sample Output
#include<iostream>
#include<iomanip>
using namespace std;
double f(int n)
{
long double a=;
for(int i=;i<=n;i++)a*=i;
return a;
}
int main()
{
cout << "n e"<<endl<<"- -----------"<<endl;
double e=;
cout<<<<" "<<e<<endl;
for(int i=;i<=;++i)
{
e+=/f(i);
cout<<i<<" ";
if(i!=) cout<<setprecision()<<e<<endl;
else cout<<setprecision()<<e<<<<endl;
}
//system("pause");
return ;
}
不难!!不要忘了long double !!!!
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