题解报告:hdu 1035 Robot Motion(简单搜索一遍)
Problem Description
A robot has been programmed to follow the instructions in its path. Instructions for the next direction the robot is to move are laid down in a grid. The possible instructions are
N north (up the page)
S south (down the page)
E east (to the right on the page)
W west (to the left on the page)
For example, suppose the robot starts on the north (top) side of Grid 1 and starts south (down). The path the robot follows is shown. The robot goes through 10 instructions in the grid before leaving the grid.
Compare what happens in Grid 2: the robot goes through 3 instructions only once, and then starts a loop through 8 instructions, and never exits.
You are to write a program that determines how long it takes a robot to get out of the grid or how the robot loops around.
Input
Output
Sample Input
Sample Output
#include<bits/stdc++.h>
using namespace std;
const int maxn=;
int row,col,st,step,cnt[maxn][maxn];char s[maxn][maxn];
void dfs(int x,int y){
while(true){//遍历一次即可
if(x<||x>=row||y<||y>=col){cout<<step<<" step(s) to exit"<<endl;return;}
if(cnt[x][y]>-){cout<<cnt[x][y]<<" step(s) before a loop of "<<(step-cnt[x][y])<<" step(s)"<<endl;return;}
//只要cnt[x][y]>-1,说明该点已经遍历过了,直接退出
cnt[x][y]=step++;
if(s[x][y]=='E')y++;
else if(s[x][y]=='W')y--;
else if(s[x][y]=='N')x--;
else x++;
}
}
int main(){
while(~scanf("%d%d%d",&row,&col,&st)&&(row+col+st)){
memset(cnt,-,sizeof(cnt));//全部初始化为-1
for(int i=;i<row;++i){
getchar();
for(int j=;j<col;++j)
scanf("%c",&s[i][j]);
}
step=;//初始值为0
dfs(,st-);
}
return ;
}
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