先在每堆中进行巴什博弈,然后尼姆

 #include<stdio.h>
int main()
{
int T;
int i,n;
int ans,m,l;
scanf("%d",&T);
while(T--)
{
scanf("%d",&n);
ans=;
for(i=;i<=n;i++)
{
scanf("%d%d",&m,&l);
ans=ans^(m%(l+));
}
if(ans==) printf("Yes\n");//后取的人胜
else printf("No\n");//先取的人胜
}
return ;
}

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