Python3解leetcode N-ary Tree Level Order Traversal
问题描述:
Given an n-ary tree, return the level order traversal of its nodes' values. (ie, from left to right, level by level).
For example, given a 3-ary
tree:
We should return its level order traversal:
- [
- [1],
- [3,2,4],
- [5,6]
- ]
Note:
- The depth of the tree is at most
1000
. - The total number of nodes is at most
5000
.
思路:此题是在leetcode上见到的第一个BFS的题目,因而记录。同时注意该句代码应用方式 Node,level = queue.pop()
代码:
- """
- # Definition for a Node.
- class Node:
- def __init__(self, val, children):
- self.val = val
- self.children = children
- """
- class Solution:
- def levelOrder(self, root: 'Node') -> List[List[int]]:
- if not root:
- return []
- result, queue = [],[(root,1)]
- while queue:
- Node,level = queue.pop()
- if level - len(result) >= 1:
- result.append([])
- result[level - 1].append(Node.val)
- for child in Node.children:
- queue.insert(0,(child,level+ 1))
- return result
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