Careercup - Microsoft面试题 - 6543214668414976

2014-05-11 02:56

题目链接

原题：

Write a function called FooBar that takes input integer n and prints all the numbers from  upto n in a new line. If the number is divisible by  then print "Foo", if the number is divisible by  then print "Bar" and if the number is divisible by both  and , print "FooBar". Otherwise just print the number.
for example FooBar() should print as follows: 

Foo 

Bar
Foo 

Foo
Bar 

Foo 

FooBar 

I know, easy right? ;)

题目：从1到n的整数，如果被3整除就输出Foo，如果被5整除就输出Bar，如果是公倍数就输出FooBar，否则直接输出原数。

解法：这题有什么陷阱？n可以是大数吗？n可以小于1吗？如果是实际面试，肯定要问清楚的。在此，我就按最简单的处理了。在这种题目上自找麻烦是没意义的。

代码：

 // http://www.careercup.com/question?id=6543214668414976
 #include <iostream>
 #include <sstream>
 using namespace std;

 int main()
 {
     int n;
     int i;

     while (cin >> n && n > ) {
         for (i = ; i <= n; ++i) {
             if (i % ) {
                 if (i % ) {
                     cout << i;
                 } else {
                     cout << "Bar";
                 }
             } else {
                 if (i % ) {
                     cout << "Foo";
                 } else {
                     cout << "FooBar";
                 }
             }
             cout << endl;
         }
     }

     return ;
 }