NYOJ-214 单调递增子序列(二) TLE 分类： NYOJ 2014-01-28 22:57 171人阅读 评论(0) 收藏

#include<stdio.h>
#include<stdlib.h>
#define max(x,y)	x>y?x:y
#define MAXX 100005
int num[MAXX] = {0};
int mum[MAXX] = {0};
int sum[2][MAXX] = {0};

int comp ( const void *a, const void *b )
{
    return * ( int * ) a - * ( int * ) b;
}

int main(){
	int n, i, j, k, d;

	while(scanf("%d",&n)!=EOF){

		for(i=1;i<=n;i++){
			scanf("%d",&num[i]);

			mum[i] = num[i];
			sum[1][i] = sum[0][i] = 0;
		}

		qsort(mum, n+1, sizeof(mum[0]), comp);

		for(i=1; i<=n; i++){

			d = i % 2;
			for(j=1; j<=n; j++){

				if(mum[i] == num[j])	sum[d][j] = sum[!d][j-1] + 1;
				else sum[d][j] = max( sum[!d][j], sum[d][j-1]);

			}
		}

		printf("%d\n",sum[d][n]);
	}
	return 0;
}

思路来源地：http://qiemengdao.iteye.com/blog/1660229

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