Problem B 迷宫寻宝

Accept: 52    Submit: 183
Time Limit: 1000 mSec    Memory Limit : 32768 KB

 Problem Description

洪尼玛今天准备去寻宝,在一个n*n (n行, n列)的迷宫中,存在着一个入口、一些墙壁以及一个宝藏。由于迷宫是四连通的,即在迷宫中的一个位置,只能走到与它直接相邻的其他四个位置(上、下、左、右)。现洪尼玛在迷宫的入口处,问他最少需要走几步才能拿到宝藏?若永远无法拿到宝藏,则输出-1。

 Input

多组测试数据。

输入第一行为正整数n,表示迷宫大小。

接下来n行,每行包括n个字符,其中字符'.'表示该位置为空地,字符'#'表示该位置为墙壁,字符'S'表示该位置为入口,字符'E'表示该位置为宝藏,输入数据中只有这四种字符,并且'S'和'E'仅出现一次。

n≤1000

 Output

输出拿到宝藏最少需要走的步数,若永远无法拿到宝藏,则输出-1。

 Sample Input

5
S.#..
#.#.#
#.#.#
#...E
#....

 Sample Output

7
 
分析:DFS,BFS基础题型,下面加一个poj2251,加深对简单搜索的理解,三维空间是3维数组,如果加上钥匙或者传送门的话就是四维空间
详情见: 2018年长沙理工大学G题 (找钥匙) 2018年湘潭大学F题 (传送门)
  1. #include <iostream>
  2. #include <algorithm>
  3. #include <vector>
  4. #include <stdlib.h>
  5. #include <string.h>
  6. #include <math.h>
  7. #include <queue>
  8. using namespace std;
  9.  
  10. #define FF(i, a, b) for(int i = a; i < b; i++)
  11. #define RR(i, a, b) for(int i = a; i > b; i++)
  12. #define ME(a, b) memset(a, b, sizeof(a))
  13. #define SC(x) scanf("%d", &x)
  14. #define PR(x) printf("%d\n", x)
  15. #define INF 0x3f3f3f3f
  16. #define MAX 1100
  17. #define MOD 1000000007
  18. #define E 2.71828182845
  19. #define M 8
  20. #define N 6
  21. typedef long long LL;
  22. const double PI = acos(-1.0);
  23. typedef pair<int, int> Author;
  24. vector<pair<string, int> > VP;
  25.  
  26. struct Node{
  27. int x, y, step;
  28. };
  29. Node bg, ed, p1, p2;
  30. queue<Node> q;
  31.  
  32. char matrix[MAX][MAX];
  33. int dir[][] = {,,-,,,,,-};
  34. int dis[MAX][MAX];
  35. int n, m, ans;
  36.  
  37. int check(int x, int y){
  38. if(x < || x >= n || y < || y >= m || dis[x][y] || matrix[x][y] == '#') return ;
  39. return ;
  40. }
  41. void Clear(queue<Node>& q){
  42. queue<Node> empty;
  43. swap(empty, q);
  44. }
  45.  
  46. int BFS(){
  47. p1 = bg;
  48. q.push(p1);dis[p1.x][p1.y] = ;
  49. while(!q.empty()){
  50. p2 = q.front();q.pop();
  51. if(p2.x == ed.x && p2.y == ed.y) return p2.step; //Í˳ö
  52. for(int i = ; i < ; i++){
  53. Node p3;
  54. p3.x = p2.x + dir[i][];
  55. p3.y = p2.y + dir[i][];
  56. p3.step = p2.step;
  57. if(!check(p3.x, p3.y)) continue;
  58. dis[p3.x][p3.y] = ;
  59. p3.step = p2.step + ;
  60. q.push(p3);
  61. }
  62. }
  63. return -;
  64. }
  65.  
  66. int main(void){
  67. // #ifdef LOCAL
  68. // freopen("in.txt", "r", stdin);
  69. // freopen("out.txt", "w", stdout);
  70. // #endif
  71. ios::sync_with_stdio(false); cin.tie();
  72. int i, j, k;
  73.  
  74. while(cin>>n){
  75. m = n;
  76. Clear(q);ME(dis, );
  77.  
  78. for(i = ; i < n; i++){
  79. for(j = ; j < m; j++){
  80. cin>>matrix[i][j];
  81. if(matrix[i][j] == 'S'){bg.x = i; bg.y = j; bg.step = ;}
  82. else if(matrix[i][j] == 'E'){ed.x = i; ed.y = j;}
  83. }
  84. }
  85.  
  86. ans = BFS();
  87. cout<<ans<<endl;
  88. }
  89. return EXIT_SUCCESS;
  90. }

POJ2251:三维空间找'S'到‘E’的距离,差不多的解法。

  1. /**
  2.  
  3. :;LaEaHKEEGpPXU7;,
  4. .:75pKH11252U252XapZgRQgD6XJscLr;,.
  5. :LXpRgGaX521JLw1JswJJsJs22XHPPEZEGDOMMRDOa7.
  6. .r2EDDZEpZPZP6KpHX5SXH5XXa5KwaXaSX5UJ1c77sLs2GMQQ6r .
  7. ,LpgOGpEZGZEZEpZKpHHU5wP5HEDgpXpHa2SSa5aSXULr7rrirrJXRBp; ;B
  8. ,J6MRZH6EgEEZE6E6EZZPZXXwSSGQXr::aPpP5USUHaHaKa5Lvrr7ri;rLHBB2: Kc
  9. rpQDOpPPOGGZOGOZG6GEOEOEDPPGBa. .PaSSUXSUUUaUSaKXKS177r7rrrirSBBR7 .O,
  10. :UBQOKPK6ZOOOEDEO6GZE6EpEpDgDBR: UBpXHa5aSaUS5SUS5XapPHJc7rrv7rr7sgBBs .g.
  11. ;gBMPXpO6GEOEOEOEGEOEE6EZEEDRGBB EB5pKSXpHKaHSX552S5aUHHEX17c7vr7777s5RBS: .R;
  12. .sQBPXpDZOODOgODGOGgEDEOEOGgGgOOMB: LBKKSXSHa52aaKXHXKaa5aSaaHXSJLcL7vcc777JDBBg2;. Qi
  13. ;2ggp2EDDOggGEDGgDDOgGGZDOOZOGg6gEBX vBZaHUKaaUXXXSXXKXpXHXH5wwaa52U1wssLsLJccv1UDQBQ67. O7
  14. :ZZUU5PROOEOZOZGGOODZOGgODZOOgOggRgRB; ;:..R6XaKKpP6PGppKPHpHpPX5aU21UUa5Sw52UwUJJv77L77sSpQMDU; ;B5
  15. ,SRJ7sSHGggEOZOEG6OODpOZgggOQQBBBBBQBBQ.,;;. LBOgOgDRDDZODMgQRgRDaa552a252UUa25w5UaU2sLvccs7r7sJZBBMr ,XQJ:
  16. LQHr77J6RGOZDZOEGEDGgDRORQBBBQRDPU1Jscwa7.,::.:J7r;::::. ..,:;i7UOgRRRgDPH5SUSU52U2HHa1JJJLJLccLr71RBB, 7R2,
  17. :RZv;77JSgGOZEODEDGOEggQBBBMS7;:,:,,.,.,.:7L;:,;.: ,: . ..... .:;rJU6GgGRggEZHPaKXX2S221Js1Lc7r:7QB. .XX:
  18. 7g1;;7rcXG6gpGDZGgZOOQBBQpr. ::::;:;:::Jr::sr;::;:.:vs,:::::::::::,, ,:7L5HGOggRgZUUU5wSUaJLc7r7BOiDr ...
  19. .XX;;;irLHGKpZZZEKgDRBBB6i ,;;:;;;;r;;:s177:,;L7:;7:.rHi,:::::::::::::::::,. .,;7ZRQgO6KUUJsLwsJ7KBM. .....
  20. JZ:;rrrc5EPHp6XgpRBBBE; :i:;;;;;:;;;:c7::r7;,::::::::rv:,:::::::::::,:,:,:,,,, .;sORQRGX21wsXU: .... .
  21. .Br;iir72EHPHZ6EgBBR7. ..;ii:;;;;;;;;;:71r::.:7, .::7;:;H;.::,:j::::::,:::::,,,::,,, ,7wEDRZBMr .......
  22. 1D;:r;rwOPXPKH6BBX, .:;:;;;:::;:;;;;;::Ls,;ss..r. ,c77;sLU,:,:::,:::,:,:,:,,,:,,,:::. .:.rP:.......
  23. D2:i;rJpKHXHXgg7 .,,::::;:::::;:;:;;:;SL7sS2, :. ::::,:U7.:::,:::,:,,,,,:,,.,,,.,:, ;L:. .. ...
  24. :Qc;i7LGZPa6gBM, ...,,::::::::::::;;::;.JJ;ic: ;:::,v1,.:::;7,,,:,:,:,,,,.:,,,,.. :2wr. .......
  25. sRr:rrwZGgBQR7. .,,::::::::::::::;::;:::Hr:7i ,;;:::U: .,,,:r.,,:,:,:,,,:,,,..... 7K2:. ..........
  26. OX:irsXgQZ:. .,,:::,,:::,::::::::;;;::r5;r7: :;;;:7L ..,.,;:,:,:,,,:,:,,,,...... .rU6w;..............
  27. .BJ71EK5;. .,,::,:,:,,,:,:,::::::::;:;.Ls;r7 :;:::s, ..,,,r:.:.,,,.:, .,..... . .;s5XJr,..,.............
  28. 1Mv::. .:,:,,,,,,,:::::::,;:::;:;::..J7;c: ,. ,rri:27 , .,:;. ,:,:,,:..,.... .rpPL;:.. ... .............
  29. ..7Ls: .,,,:,,,:,:,:::,:,:::::,:::::: .Srrr, .,:;;;::::..:7r;r1 .: :E:..,,:,...,,.., ..XBQ7, ................... ..
  30. ,;7v7r7:, ,,,,:.,,,,,,:,,::,:,,.::.,:.,:, :Jrr; ,r7,:.. ,:::L: . .7RJ .,.:.,......,,:MBs ..............,........
  31. .:;vJs7i, ,,,., ..,,:,,,:,,,:,:.,rs,,.:,, ;J;c, .,::;; Lr.E: .,...,....:,:1Z: .........,.,...........:,.
  32. .;,,:r7J1wv;,. ....,.:. .,.,,:,,,:,,::::,sS;.:::, cLrr. . .,. .,..: ;; r5 ........,,:;s7. ....,.,.,...........,.,.,,.
  33. ,BBs::: . ........,.,,,,,.:,,,:,:,,.;s7r,,,,, cc7; ,.,,. .:7rrJGMPOEL1, ..... ,,:rSr, : ,.,.,.,.,.........,,,,,. ..
  34. rZL. ....... ..,,,.,,,..,,,.,;,...7J:s: .. .wr7, ... .rJpQBBBBBBBQgKP77s .. .,7S2,,....,....,.,.,......,,.,. .:cX2
  35. ;SH7, . . . .. .,.,.,.,,,...,..r, ::Ur;7L . .57;. .rPBBQBBBPws:;r::::.,:P. .;S5;,..,...,.,.,.,.... ..,,, ..,7HSJvr
  36. r7r;: . ... ..........,...,.. 7L;,rS;;ivr . 1r: . .rZBBK7;.JL,::Jrs;.:;,:;J, .,;LDv..:.,...,.,.,.,...,.,,:,, ,7sKGwc77;
  37. .:7L7:, . ,r,..,.,,,...,..:iLL 7s;r;cv: U7. :vi;:. .. :Er:::.Ls. . ,7::::vHEi ,:,,.,,,.,.,,,,,,::::, .:1QBKJJUsssc
  38. .:rvw1JsL7;, ,;..........,.:ir :r .ELr77v:,. Pr .. . Ls ,w. rr.r:JPr. ::,..,,,.,,,,:,:::,:,..7XgRE52US25w1c
  39. .:;7JRQpX: ; .........,i: .,J ;gri;7r : 1; .X: . ,v :aK1, ,,:.,,,.,,,,:::::,;::::cOBB6K55UXUX5XUw
  40. ;J,XQB7,: . ...,: .:7Z.7Zi7;r: , v, :w:;,.,:::7LUsc:..:,:.:,,,,,:,:::::::,:;c5BBPS5wSUSUaUaUa2
  41. J7 rEBBg..,. ..... . ,L1PLKr:,:;r;;::, :, :;SXsJU1XLLr....:,,,,,,::::,::::::,::LL,,rZXUJU25552aUUUU
  42. JL .:sXBB:... ., . ,OH777;,rZRBBBQL ..r, ,:r7::r:,;;....:,,,,,,,,.::::;::;:::.7gL UK2UUS1aw2wU25J
  43. U7 .r71BB; . :.. .. :QJ;.;1pBBBBBGRBRi i: . .w7. ..,,:,,,,,:,:,:::::::,.,2BR: .DSaUSUUS525w5U1
  44. 2r :7rJBQ7 .;. . KL::JGBBBgE6Hp6XMQ; . ... ,2s ,,,,:::::,:::::::,,.:sQQB2 ;DHa5U52S2U25USJ
  45. a: :7;1BB2 .v, sL;LPQgDBPH6KPQBpGBG . ... .. aP:. .. ,::,:::::,,,,.;rSgBQDa; :gSSwSUUU525US2U
  46. 5; ;;r2QBB, .s: :a7:PBZ2,:BEaZPKgBZOgB, . ...:LEHri::,:.,,.,,,::rsXRBgGKEJi, 2GH252SUS5S11wH5
  47. U: ;:rwDBBr .c, rB6r 167.,,RQPpEP6OpKEBc ., . : ::sS7;cKB6HHa1XOQRRQBRgEZDBH; .. ;RZUPSSU525USSpK2
  48. s; ;::aBg, .; .Gv,H::,,::,;BQDOGHPXpKBs .,. . .,. .r:;:6gOEBQRRRDggQgOHgMGL, .;PEHHXaaKaPXPKPaXS
  49. s7.:,sBa :..S, vE::::; 7BBMgZH6pQBr . ,:, ,.,r2RHSSpMZPKRRZpgggav, ;UpEZaaaKHHUHPPaUJHGO
  50. a;.775: .::rU. gR:,:. :;:BBBBQar . ,, ,.,7rggJwU6DDGMgOGgXc:, ,rPGOpKSXSXSKUKHU1UHgOEP
  51. 1i :SZJrLXpBBMRB: .v Ba,. :sv: . irsBUSpEEGPPpg65r:..,;sKZDZHSX5XaHU55K2wUGMRZ6Z6
  52. :K :7asvwc2MgEQB, :gg.:iB7 .,,,:. ...,. . .. .:iM6GEpSSXZOEs:...;spZpKKXXSX5Xa5Ja5wwKGQDEpp6OZ
  53. w; ,LXLr77sLwL5aR. gRgQgaQBi ,vJwvi,. .;;:;7: . . ,... rRDRJUSXpgas:,.:;U66SaHa2X5aUa552X12SgQgpZpEpGOD
  54. H: ;XJ;77rv7rJUaQ;rgaPgXXHBB; . . .ri:;; ,: . :6QZEKHXpXXL:,::r1PKXaa2XSS5a5S5UJ22aOBgEpOppZOOgG
  55. iwsJsr7rsLrrLcJ2gQGXHwa1SUHBB: . ... . .., : 1BRKpOEGp2Jr;::rsXP1Uaa2U5a5aUa5SsSpgQRZGZEEZZOOgDg
  56. ,cs5aXaP552ssLwRSHXaSS5asXBB. . . . LBBgGgZHsr;vrr;rcXpP5UUS5X5S2XS5SS1URBggpEZgDDGOGggRD
  57. ,;irrs2KgQRPJJJSUXKXSHJpBM . . . ZBBOUsr;:. ,,,rHgZPUaSaUSUSSXaUPXsSBB6ZZp6EEGOOGDEggO
  58. ;BBQQZaSJ5J15SJDQ7 .iEBL:. . .,:,:;SRQGZXPXXSHaS2UUSUSswQB6OZgG6pZZGODEOGDE
  59. JgUri1aGEpEpXSS5LBQ, .rLap2Jr ;712OO6ZggRDZXHXpKK2211LLLc7wgBa2PODRGE6OZgDgGDGD
  60. 7QB; ,Jc76DaZXOZgDPEBBX, :c1HEZ1c;:,.,:;cHDgQQggMZgGOZO6OEGpXsLLsJXHPOBBBc;vss5EMggZDODOgED6
  61. LZJ::iwrrr72EPgXU5OBBBBBBBp7: .i5P6wL;, .:LS6DMgMgZKgEOPOGGDDGEXULvLSOBBBBBQBgDQDJ5rrr7JOQQDDZGEgDD
  62. wp rR5, .HQRX7r72RQBBBBBQBMEK6Uc7sc7cHOU:, .:LHgOQg6ZOPZpZGGEDERZPwcr7LKDDaJr:. rBX;;:r:ir1DBQMgRgDp
  63. 7D,sw: , Z. .LgBBQBBOsJaQBBBBBBXrr. .:rwZBBQgROgDgDOERRMgROOScrLsPP5r, 7Qs,::::::rUgRgZOG6
  64. ,Q57:r ,: ,r U: .;; .vL7L;r:UG7.:sr;JSgQBgDEZXXUSXpHa21svr7r7s2v:. iQK...:,:::;LLJJws
  65. OBHs;. :;;,v H: :6X; rpL;7pSrrr7r;::,....,,:;iirrvvvr, :BBPs;;:,,,,::;::
  66. ::rPDEL:..7:c;7r pK .: :KL.:r:.. ..:icsS5sr:,. JgGgBQDOSJss77r
  67. :r;::: , PH r, ,;5: ,::::;7Ls7Lc7;: ,:7JP17rJUs
  68. .:J: :; .,:K6BQS7:.,.,.
  69. :r7Ji;r7;::;;.
  70. . **/
  71.  
  72. #include <iostream>
  73. #include <algorithm>
  74. #include <vector>
  75. #include <stdlib.h>
  76. #include <string.h>
  77. #include <math.h>
  78. #include <queue>
  79. using namespace std;
  80.  
  81. #define FF(i, a, b) for(int i = a; i < b; i++)
  82. #define RR(i, a, b) for(int i = a; i > b; i++)
  83. #define ME(a, b) memset(a, b, sizeof(a))
  84. #define SC(x) scanf("%d", &x)
  85. #define PR(x) printf("%d\n", x)
  86. #define INF 0x3f3f3f3f
  87. #define MAX 35
  88. #define MOD 1000000007
  89. #define E 2.71828182845
  90. #define M 8
  91. #define N 6
  92. typedef long long LL;
  93. const double PI = acos(-1.0);
  94. typedef pair<int, int> Author;
  95. vector<pair<string, int> > VP;
  96.  
  97. struct Node{
  98. int x, y, z, step;
  99. };
  100. Node bg, ed, p1, p2;
  101. queue<Node> q;
  102.  
  103. char matrix[MAX][MAX][MAX];
  104. int dir[][] = {,,,-,,,,,,,-,,,,,,,-};
  105. int dis[MAX][MAX][MAX];
  106. int n, m, l, ans;
  107.  
  108. int check(int x, int y, int z){
  109. if(x < || x >= n || y < || y >= m || z < || z >= l || dis[x][y][z] || matrix[x][y][z] == '#') return ;
  110. return ;
  111. }
  112. void Clear(queue<Node>& q){
  113. queue<Node> empty;
  114. swap(empty, q);
  115. }
  116.  
  117. int BFS(){
  118. p1 = bg;
  119. q.push(p1);dis[p1.x][p1.y][p1.z] = ;
  120. while(!q.empty()){
  121. p2 = q.front();q.pop();
  122. if(p2.x == ed.x && p2.y == ed.y && p2.z == ed.z) return p2.step; //退出
  123. for(int i = ; i < ; i++){
  124. Node p3;
  125. p3.x = p2.x + dir[i][];
  126. p3.y = p2.y + dir[i][];
  127. p3.z = p2.z + dir[i][];
  128. p3.step = p2.step;
  129. if(!check(p3.x, p3.y, p3.z)) continue;
  130. dis[p3.x][p3.y][p3.z] = ;
  131. p3.step = p2.step + ;
  132. q.push(p3);
  133. }
  134. }
  135. return ;
  136. }
  137.  
  138. int main(void){
  139. #ifdef LOCAL
  140. freopen("in.txt", "r", stdin);
  141. freopen("out.txt", "w", stdout);
  142. #endif
  143. ios::sync_with_stdio(false); cin.tie();
  144. int i, j, k;
  145.  
  146. while(cin>>l>>n>>m){
  147. if(l <= || n <= || m <= ) break;
  148. Clear(q);ME(dis, );
  149.  
  150. for(k = ; k < l; k++){
  151. for(i = ; i < n; i++){
  152. for(j = ; j < m; j++){
  153. cin>>matrix[i][j][k];
  154. if(matrix[i][j][k] == 'S'){bg.x = i; bg.y = j; bg.z = k; bg.step = ;}
  155. else if(matrix[i][j][k] == 'E'){ed.x = i; ed.y = j; ed.z = k;}
  156. }
  157. }
  158. }
  159.  
  160. ans = BFS();
  161. if(ans) cout<<"Escaped in "<<ans<<" minute(s)."<<endl;
  162. else cout<<"Trapped!"<<endl;
  163.  
  164. }
  165. return EXIT_SUCCESS;
  166. }

福州大学第十五届程序设计竞赛_重现赛B题迷宫寻宝的更多相关文章

  1. 北京师范大学第十六届程序设计竞赛决赛-重现赛-B题

    一.题目链接 https://www.nowcoder.com/acm/contest/117/B 二.题意 给定一组序列$a_1,a_2,\cdots,a_n$,表示初始序列$b_1,b_2,\cd ...

  2. 长春理工大学第十四届程序设计竞赛(重现赛)M.Orx Zone

    链接:https://ac.nowcoder.com/acm/contest/912/M 题意: Daenerys Stormborn, 风暴中出生的丹尼莉丝,the Unburnt, 烧不死的,Qu ...

  3. 长春理工大学第十四届程序设计竞赛(重现赛)L.Homework Stream

    链接:https://ac.nowcoder.com/acm/contest/912/L 题意: 作为大珩班尖子生,小r每天有很多作业要完成,例如工图.工图和工图. 很显然,做作业是要有顺序的.作业之 ...

  4. 长春理工大学第十四届程序设计竞赛(重现赛)J.Printout

    链接:https://ac.nowcoder.com/acm/contest/912/J 题意: 小r为了打校赛,他打算去打字社打印一份包含世界上所有算法的模板. 到了打字社,小r一看价格:总打印页数 ...

  5. 长春理工大学第十四届程序设计竞赛(重现赛)I.Fate Grand Order

    链接:https://ac.nowcoder.com/acm/contest/912/I 题意: Fate Grand Order是型月社发行的角色扮演类手机游戏,是著名的氪金抽卡"垃圾&q ...

  6. 长春理工大学第十四届程序设计竞赛(重现赛)H.Arithmetic Sequence

    题意: 数竞选手小r最喜欢做的题型是数列大题,并且每一道都能得到满分. 你可能不相信,但其实他发现了一个结论:只要是数列,无论是给了通项还是给了递推式,无论定义多复杂,都可以被搞成等差数列.这样,只要 ...

  7. 长春理工大学第十四届程序设计竞赛(重现赛)F.Successione di Fixoracci

    链接:https://ac.nowcoder.com/acm/contest/912/F 题意: 动态规划(Dynamic programming,简称dp)是一种通过把原问题分解为相对简单的子问题的 ...

  8. 长春理工大学第十四届程序设计竞赛(重现赛)B.Bowling Game

    链接:https://ac.nowcoder.com/acm/contest/912/B 题意: 链接:https://ac.nowcoder.com/acm/contest/912/B来源:牛客网 ...

  9. 长春理工大学第十四届程序设计竞赛(重现赛)J

    J.Printout 题目:链接:https://ac.nowcoder.com/acm/contest/912/J 题目: 小r为了打校赛,他打算去打字社打印一份包含世界上所有算法的模板. 到了打字 ...

随机推荐

  1. iOS应用图标及尺寸

    Icon and Image Sizes Every app needs an app icon and a launch file or image. In addition, some apps ...

  2. C++ 执行 cmd 命令 删除文件 删除注册表项

    #include <Windows.h> WinExec("cmd /C \"del C:\\Windows\\secretWin.ini\"",S ...

  3. 问题:mysql服务正在启动 mysql服务无法启动 && mysql启动脚本 mysql关闭脚本

    此篇目编写两个核心目的: 1.mysql服务启动脚本(start_mysql.bat),mysql服务停止脚本(stop_mysql.bat)的讲解. 2.解决问题:mysql服务无法启动. 操作流程 ...

  4. js区别手机和电脑打开网页

    Navigator对象 首先来了解一下Navigator 对象,Navigator 对象包含有关浏览器的信息,下面的userAgent 属性是一个只读的字符串,声明了浏览器用于 HTTP 请求的用户代 ...

  5. python之mysqldb模块安装

    之所以会写下这篇日志,是因为安装的过程有点虐心.目前这篇文章是针对windows操作系统上的mysqldb的安装.安装python的mysqldb模块,首先当然是找一些官方的网站去下载:https:/ ...

  6. spring aop:aspectj-autoproxy 配置

    经常遇到aop-aspectJ的通知不被执行的问题 解决方法:http://blog.csdn.net/qwdafedv/article/details/53005210 首先,确保配置文件都已经是正 ...

  7. html5-列表

    <!DOCTYPE html><html lang="en"><head>    <meta charset="UTF-8&qu ...

  8. XML文件怎么添加注释

    注释以 <!-- 开始并以 --> 结束,例如 <!--注释内容-->.   注释可以出现在文档序言中,包括文档类型定义 (DTD):文档之后:或文本内容中. 注释不能出现在属 ...

  9. 激活win10

    网盘地址 http://pan.baidu.com/s/1nvc5I1V 里面是2个东西,一个是rar解压缩软件,一个是激活工具本体 一个解压缩软件,一个激活工具的压缩包 安装解压软件,就是WINRA ...

  10. 干货 | JavaScript内存空间详解

    JS栈内存与堆内存 var a = 20; var b = 'abc'; var c = true; var d = { m: 20 } 因为JavaScript具有自动垃圾回收机制,所以对于前端开发 ...