Moving Tables(贪心或Dp POJ1083)
Time Limit: 1000MS | Memory Limit: 10000K | |
Total Submissions: 28304 | Accepted: 9446 |
Description
The floor has 200 rooms each on the north side and south side along the corridor. Recently the Company made a plan to reform its system. The reform includes moving a lot of tables between rooms. Because the corridor is narrow and all the tables are big, only
one table can pass through the corridor. Some plan is needed to make the moving efficient. The manager figured out the following plan: Moving a table from a room to another room can be done within 10 minutes. When moving a table from room i to room j, the
part of the corridor between the front of room i and the front of room j is used. So, during each 10 minutes, several moving between two rooms not sharing the same part of the corridor will be done simultaneously. To make it clear the manager illustrated the
possible cases and impossible cases of simultaneous moving.
For each room, at most one table will be either moved in or moved out. Now, the manager seeks out a method to minimize the time to move all the tables. Your job is to write a program to solve the manager's problem.
Input
move.
Each of the following N lines contains two positive integers s and t, representing that a table is to move from room number s to room number t each room number appears at most once in the N lines). From the 3 + N -rd
line, the remaining test cases are listed in the same manner as above.
Output
Sample Input
3
4
10 20
30 40
50 60
70 80
2
1 3
2 200
3
10 100
20 80
30 50
Sample Output
10
20
30
Source
开始做的时候用的贪心后来感觉好麻烦,就又写的Dp;
贪心
#include <iostream>
#include <cstdio>
#include <cstring>
#include <cstdlib>
#include <algorithm> using namespace std; typedef struct node
{
int L;
int R;
bool operator <(const node &a)const
{
if(L<a.L||(L==a.L&&R<a.R))
{
return true;
}
return false;
}
} Edge; Edge a[300]; bool vis[300]; int main()
{
int T,n,x,y;
scanf("%d",&T);
while(T--)
{
scanf("%d",&n);
for(int i=0; i<n; i++)
{
scanf("%d %d",&x,&y);
if(x>y)
{
swap(x,y);
}
if(x&1)
{
a[i].L=(x+1)/2;
}
else
{
a[i].L=x/2;
}
if(y&1)
{
a[i].R=(y+1)/2;
}
else
{
a[i].R=y/2;
} }
sort(a,a+n);
memset(vis,false,sizeof(vis));
int sum=0;
while(1)
{
int ans=-1;
for(int i=0; i<n; i++)
{
if(!vis[i])
{
if(a[i].L>ans)
{
ans=a[i].R;
vis[i]=true;
}
}
}
if(ans==-1)
{
break;
}
else
{
sum++;
}
}
printf("%d\n",sum*10);
}
return 0;
}
Dp
#include <iostream>
#include <cstdio>
#include <cstring>
#include <cstdlib>
#include <algorithm>
using namespace std;
int Dp[201];
int main()
{
int T,n,x,y;
scanf("%d",&T);
while(T--)
{
scanf("%d",&n);
memset(Dp,0,sizeof(Dp));
for(int i=0; i<n; i++)
{
scanf("%d %d",&x,&y);
if(x>y)
{
swap(x,y);
}
x=(x+1)/2;
y=(y+1)/2;
Dp[x]+=1;
Dp[y+1]-=1;
}
int sum=0;
for(int i=1;i<201;i++)
{
Dp[i]+=Dp[i-1];
sum=max(sum,Dp[i]);
}
printf("%d\n",sum*10);
}
return 0;
}
Moving Tables(贪心或Dp POJ1083)的更多相关文章
- zstu.2512. Moving Tables(贪心)
Moving Tables Time Limit: 1 Sec Memory Limit: 64 MB Submit: 1182 Solved: 563 Description The famo ...
- HDU1050(Moving Tables:贪心算法)
解题思路: 这种做法是基于hdu2037的做法上考虑的,找出所有可以同时搬运的桌子,然后就很方便求出最短总时间. 还有一种更简单的做法是直接遍历一遍找出与别的重复次数最多的那片区域,重复次数*10就可 ...
- hdu_1050 Moving Tables 贪心
Moving Tables Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)Tot ...
- UVAlive 2326 Moving Tables(贪心 + 区间问题)
The famous ACM (Advanced Computer Maker) Company has rented a floor of a building whose shape is in ...
- --hdu 1050 Moving Tables(贪心)
题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=1050 AC code: #include<stdio.h> #include<str ...
- hdoj 1050 Moving Tables【贪心区间覆盖】
Moving Tables Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)Tot ...
- POJ1083 Moving Tables
POJ1083 Moving Tables Time Limit: 1000MS Memory Limit: 10000K Total Submissions: 35297 Accepted: ...
- POJ 1083 && HDU 1050 Moving Tables (贪心)
Moving Tables Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others) To ...
- HDOJ 1050 Moving Tables
Moving Tables Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)Tot ...
随机推荐
- win10我能ping通他人,但他人ping不同我
这是防火墙的原因,关闭防火墙即可
- Hibernate的一级二级缓存机制配置与测试
特别感谢http://www.cnblogs.com/xiaoluo501395377/p/3377604.html 在本篇随笔里将会分析一下hibernate的缓存机制,包括一级缓存(session ...
- Oracle常见SQL语句
--创建表空间--create tablespace ts_namedatafile 'd:\test\ts_name.dbf' size 100mautoextend on --调整表空间大小--a ...
- A+B Problem III-(涉及误差)NYOJ-477
描述求A+B是否与C相等. 输入 T组测试数据. 每组数据中有三个实数A,B,C(-10000.0<=A,B<=10000.0,-20000.0<=C<=20000.0) ...
- java 正则表达式获取匹配和非获取匹配
package test1; import java.util.regex.Matcher; import java.util.regex.Pattern; public class TestExp ...
- js树形控件
js树形控件 ztree http://www.treejs.cn/
- MVC控制器取参数值
1.这个方法是获取提交表单里的参数值,也就是有name="xxx"的属性的表单控件的值 FormCollection传值 public ActionResult Login(For ...
- 一个php的爬虫,将笔趣阁的书可以都下载下来。
数据库:book 表id ---- 数据库: `book`-- -- -------------------------------------------------------- ---- 表的结 ...
- memcache的windows下的安装和简单使用
原文:memcache的windows下的安装和简单使用 memcache是为了解决网站访问量大,数据库压力倍增的解决方案之一,由于其简单实用,很多站点现在都在使用memcache,但是memcach ...
- 使用 HTML5 input 类型提升移动端输入体验
在过去的几年里,在移动设备上浏览网页已变得难以置信的受欢迎. 但是这些设备上的浏览体验,有时遗留很多的有待改进.当涉及到填写表单时,这一点尤为明显.幸运的是,HTML5规范引入了许多新input类型, ...