Codeforces 437C The Child and Toy(贪心)

题目连接：Codeforces 437C  The Child and Toy

贪心，每条绳子都是须要割断的，那就先割断最大值相应的那部分周围的绳子。

#include <iostream>
#include <cstring>
#include <cstdio>
#include <algorithm>

using namespace std;

const int MAX_N = 1000 + 10;
int G[MAX_N][MAX_N];

struct Value
{
    int val;
    int i;
};
int cmp(Value a, Value b)
{
    return a.val > b.val;
}
Value value[MAX_N];
int value1[MAX_N];

int main()
{
    memset(G, 0, sizeof(G));
    int n, m;
    scanf("%d%d", &n, &m);
    for(int i = 1;i <= n; i++)
    {
        scanf("%d", &value[i].val);
        value1[i] = value[i].val;
        value[i].i = i;
    }
    int u, v;
    for(int i = 0; i < m; i++)
    {
        scanf("%d%d", &u, &v);
        G[u][v] = G[v][u] = 1;
    }
    sort(value + 1, value + n + 1, cmp);
    int sum = 0;
    int b;
    for(int i = 1; i <= n; i++)
    {
        b = value[i].i;
        for(int j = 1; j <= n; j++)
        {
            if(G[b][j])
            {
                sum += value1[j];
                G[b][j] = G[j][b] = 0;
            }
        }
    }
    printf("%d\n", sum);
    return 0;
}