hdoj 5249 KPI(treap)

题目链接：http://acm.hdu.edu.cn/showproblem.php?pid=5249

思路分析：使用queue记录管道中的值并使用treap能够查询第K大的功能查询第floor(m/2)+1大的数值；

对于in value操作，将value插入queue中和treap中；对于out操作，在treap中删除queue中队头元素，并在queue中使队头元素出队；

对于query操作，因为tail – head的值即为管道中的值的个数，使用treap查询第floor((tail – head) / 2) + 1大的元素即可；

代码如下：

#include <cstdio>
#include <ctime>
#include <cstring>
#include <iostream>
using namespace std;
 
const int MAX_N =  + ;
int queue[MAX_N];
 
struct Node{
    Node *ch[];
    int value, key;
    int size;
    int cmp(int x) const{
        if (x == value) return -;
        return x < value ?  : ;
    }
    void Maintain(){
        size = ;
        if (ch[] != NULL) size += ch[]->size;
        if (ch[] != NULL) size += ch[]->size;
    }
};
 
void Rotate(Node *&o, int d){
    Node *k = o->ch[d ^ ];
    o->ch[d ^ ] = k->ch[d];
    k->ch[d] = o;
    o->Maintain();
    k->Maintain();
    o = k;
}
 
void Insert(Node *&o, int x){
    if (o == NULL){
        o = new Node();
        o->ch[] = o->ch[] = NULL;
        o->value = x;
        o->key = rand();
    }
    else{
        int d = (x < (o->value) ?  : );
        Insert(o->ch[d], x);
        if (o->ch[d]->key > o->key)
            Rotate(o, d ^ );
    }
    o->Maintain();
}
 
void Remove(Node *&o, int x){
    int d = o->cmp(x);
 
    if (d == -){
        Node *u = o;
 
        if (o->ch[] != NULL && o->ch[] != NULL){
            int d2 = (o->ch[]->key > o->ch[]->key ?  : );
 
            Rotate(o, d2);
            Remove(o->ch[d2], x);
        }else{
            if (o->ch[] == NULL)
                o = o->ch[];
            else
                o = o->ch[];
            delete u;
        }
    }else
        Remove(o->ch[d], x);
    if (o != NULL)
        o->Maintain( );
}
 
int Find(Node *o, int x){
    while (o != NULL){
        int d = o->cmp(x);
 
        if (d == -) return ;
        else o = o->ch[d];
    }
    return ;
}
 
int FindKth(Node *o, int k){
    int l_size = (o->ch[] == NULL ?  : o->ch[]->size);
    if (k == l_size + )
        return o->value;
    else if (k <= l_size)
        return FindKth(o->ch[], k);
    else
        return FindKth(o->ch[], k - l_size - );
}
 
void MakeEmpty(Node *root){
    if (root == NULL)
        return;
    if (root->ch[])
        MakeEmpty(root->ch[]);
    if (root->ch[])
        MakeEmpty(root->ch[]);
    delete root;
}
 
int main(){
    int n, case_id = , value;
 
    srand();
    while (scanf("%d", &n) != EOF){
        Node *root = NULL;
        int head = , tail = , ans;
        char str[];
 
        printf("Case #%d:\n", ++case_id);
        for (int i = ; i < n; ++i){
            scanf("%s", str);
            if (str[] == 'i'){
                scanf("%d", &value);
                queue[tail++] = value;
                Insert(root, value);
            }
            else if (str[] == 'o')
                Remove(root, queue[head++]);
            else{
                ans = FindKth(root, (tail - head) /  + );
                printf("%d\n", ans);
            }
        }
        MakeEmpty(root);
    }
    return ;
}