Big Number

Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 5857    Accepted Submission(s):
4093
点我

Problem Description
As we know, Big Number is always troublesome. But it's
really important in our ACM. And today, your task is to write a program to
calculate A mod B.

To make the problem easier, I promise that B will be
smaller than 100000.

Is it too hard? No, I work it out in 10 minutes, and
my program contains less than 25 lines.

 
Input
The input contains several test cases. Each test case
consists of two positive integers A and B. The length of A will not exceed 1000,
and B will be smaller than 100000. Process to the end of file.
 
Output
For each test case, you have to ouput the result of A
mod B.
 
Sample Input
2 3
12 7
152455856554521 3250
 
Sample Output
2
5
1521
 #include <iostream>
#include <cstring>
using namespace std;
int main()
{
int n,i,j;
char a[];
while(cin>>a>>n)
{
int count=,c=,m=;
count=strlen(a)-;
for(i=;i<=count;i++)
{
m=a[i]-''+c*;
c=m%n;
}
cout<<c<<endl;
memset(a,,sizeof(a));
}
}

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