PHP每日签到及连续签到奖励实现示例

数据库字段

num 记录已经连续签到次数

times 记录签到的日期 格式年月日 如 20160101

PHP代码如下

<?php
//获取今天的日期
$today = date('Ymd');
//获取签到记录
$signInfo = M('table')->field('id,num,times')->where(array('uid' => session('uid')))->find();

if($signInfo['times'] == $today){//今天已签到过了
    $this->ajaxReturn(array('info' => '今天已签到过了', 'status' => 0));

}elseif($signInfo['times'] == date('Ymd', strtotime('-1 day'))){//昨天已签到，连续签到处理
    if ($signInfo['num'] == 29) {//连续签到30天，每30天清零
        $num = 0;//连续签到次数
        $point = 30;//额外奖励积分数
    }elseif($signInfo['num'] == 20){//连续签到3周
        $num = $signInfo['num'] + 1; $point = 20;
    }elseif($signInfo['num'] == 13){//连续签到2周
        $num = $signInfo['num'] + 1; $point = 15;
    }elseif($signInfo['num'] == 6){//连续签到1周
        $num = $signInfo['num'] + 1; $point = 10;
    }else{
        $num = $signInfo['num'] + 1; $point = 0;
    }
    //更新签到记录
    $result = M('table')->save(array('uid' => session('uid'), 'num' => $num, 'times' => $today));

}else{//断签或未签到过，重新计数
    $point = 0;
    if ($signInfo['id']) {//有签到记录，更新记录信息
        $result = M('table')->save(array('uid' => session('uid'), 'num' => 1, 'times' => $today));
    }else{//无签到记录，添加一条记录
        $result = M('table')->add(array('uid' => session('uid'), 'num' => 1, 'times' => $today));
    }
}

if ($result){
    $points = $point + 3;//本次签到获得的总积分数 = 额外奖励 + 签到一次应得的积分数 此处为3分
    $result = M()->execute('update users set total_point=total_point+' . $points . ',now_point=now_point+' . $points . ' where uid=' . session('uid'));
    if($result){
        $msg = '签到成功，获得3积分';
        $msg .= $point > 0 ? '<br />连续签到' . ($num > 0 ? $num : 30) . '天，奖励' . $point . '积分' : '';
        $this->ajaxReturn(array('info' => $msg, 'status' => 1));
    }
}
$this->ajaxReturn(array('info' => '签到失败', 'status' => 0));

代码是根据ThinkPHP框架开发，在项目代码的基础上进行了修改，项目代码运行正常，修改后的上述代码没有实际运行过，只作为开发思路参考