Ignatius and the Princess IV

Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32767 K (Java/Others)
Total Submission(s): 13294    Accepted Submission(s): 5362

Problem Description
"OK, you are not too bad, em... But you can never pass the next test." feng5166 says.

"I will tell you an odd number N, and then N integers. There will be a special integer among them, you have to tell me which integer is the special one after I tell you all the integers." feng5166 says.

"But what is the characteristic of the special integer?" Ignatius asks.

"The integer will appear at least (N+1)/2 times. If you can't find the right integer, I will kill the Princess, and you will be my dinner, too. Hahahaha....." feng5166 says.

Can you find the special integer for Ignatius?

 
Input
The input contains several test cases. Each test case contains two lines. The first line consists of an odd integer N(1<=N<=999999) which indicate the number of the integers feng5166 will tell our hero. The second line contains the N integers. The input is terminated by the end of file.
 
Output
For each test case, you have to output only one line which contains the special number you have found.
 
Sample Input
5
1 3 2 3 3
11
1 1 1 1 1 5 5 5 5 5 5
7
1 1 1 1 1 1 1
 
Sample Output
3
5
1
 
思路:用a[i]记录i出现的次数,这样就可以避免因大量查找而超时
 
#include<stdio.h>
#include<string.h>
int a[];
int
main()
{

int
n,i,j,max;
while
(~scanf("%d\n",&n))
{

memset(a,,sizeof(a));
for
(i =;i < n;i ++)
{

scanf("%d",&j);
a[j]++;
if
(a[j]>=(n+)/)
max = j;
}

printf("%d\n",max);
}

return
;
}

Ignatius and the Princess IV的更多相关文章

  1. hdu 1029 Ignatius ans the Princess IV

    Ignatius and the Princess IV Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32767 K ( ...

  2. HDU 1029 Ignatius and the Princess IV --- 水题

    HDU 1029 题目大意:给定数字n(n <= 999999 且n为奇数 )以及n个数,找出至少出现(n+1)/2次的数 解题思路:n个数遍历过去,可以用一个map(也可以用数组)记录每个数出 ...

  3. Ignatius and the Princess IV(乱搞一发竟然过了)

    B - Ignatius and the Princess IV Time Limit:1000MS     Memory Limit:32767KB     64bit IO Format:%I64 ...

  4. HDU 1029 Ignatius and the Princess IV / HYSBZ(BZOJ) 2456 mode(思维题,~~排序?~~)

    HDU 1029 Ignatius and the Princess IV (思维题,排序?) Description "OK, you are not too bad, em... But ...

  5. (Arrays.sort() 或 map) Ignatius and the Princess IV hdu1029

    Ignatius and the Princess IV 链接:http://acm.hdu.edu.cn/showproblem.php?pid=1029 借鉴链接:https://blog.csd ...

  6. HDU 1029 Ignatius and the Princess IV (map的使用)

    传送门: http://acm.hdu.edu.cn/showproblem.php?pid=1029 Ignatius and the Princess IV Time Limit: 2000/10 ...

  7. HDOJ.1029 Ignatius and the Princess IV(map)

    Ignatius and the Princess IV 点我跳转到题面 点我一起学习STL-MAP 题意分析 给出一个奇数n,下面有n个数,找出下面数字中出现次数大于(n+1)/2的数字,并输出. ...

  8. kuangbin专题十二 HDU1029 Ignatius and the Princess IV (水题)

    Ignatius and the Princess IV Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32767 K ( ...

  9. [ACM] hdu 1029 Ignatius and the Princess IV (动归或hash)

    Ignatius and the Princess IV Time Limit : 2000/1000ms (Java/Other)   Memory Limit : 65536/32767K (Ja ...

随机推荐

  1. 开始学习requirejs+easyui的使用.

    开始学习requirejs+easyui的使用. 目录结构: |-project |-easyui01 |-js |-main.js |-index.html |-libs libs目录下放入的是ea ...

  2. c++primer复习(一)

    1 const对象默认为文件的局部变量(P50) a.cpp ; b.cpp extern int a;//undefined reference to "a" a.cpp ; b ...

  3. Mysql备份数据库的一种方法

    今天添加了一个数据库自动备份的模块,mysql数据备份的方法有很多,可以对单个数据库备份,可以多个数据库备份,也可以对某一个表进行备份,可以只备份数据库的结构不备份数据,可以根据需要做不同处理,正好现 ...

  4. HeadFirst设计模式

    oo基础 抽象 封装 多态 继承 oo原则 封装变化 多用组合,少用继承 针对接口编程,不针对实现编程(策略模式) 为交互对象之间的松耦合设计而努力(观察者模式) 对扩展开放,对修改关闭(装饰者模式) ...

  5. ubuntu 安装phpmyadmin

    参考文章: http://www.111cn.net/database/mysql/43957.htm    access错误的解决方法 1 首先下载  去官网下载phpmyadmin 2  然后直接 ...

  6. 【转】Oracle job procedure 存储过程定时任务

    原文:Oracle job procedure 存储过程定时任务 oracle job有定时执行的功能,可以在指定的时间点或每天的某个时间点自行执行任务. 一.查询系统中的job,可以查询视图 --相 ...

  7. PHP对URL设置

    一.URL规则  1.默认是区分大小写的  2.如果我们不想区分大小写可以改配置文件   'URL_CASE_INSENSITIVE'=>true,               //url不区分 ...

  8. Vim 中文件目录浏览插件——NERD tree

    说明 :vim的插件NERDTree用于使得vim窗口分左右窗口显示的用法说明.其中,左侧为目录的树形界面,简称为NERDTree界面,右则为vim界面. 一.配置步骤 下载地址: http://ww ...

  9. 事件tou

    #define EV_TIMER_RESOLUTION 1 /* 1 msec */ #define EV_READ_EVENT EPOLLIN #define EV_WRITE_EVENT EPOL ...

  10. hdu 4762 && 2013 ACM/ICPC 长春网络赛解题报告

    这次的答案是猜出来的,如果做得话应该是应该是一个几何概型的数学题: 答案就是:n/(m^(n-1)); 具体的证明过程: 1.首先枚举这M个点中的的两个端点,概率是:n*(n-1); 2.假设这个蛋糕 ...