python 练习 simple_server 判断路径及返回函数

函数 routers 返回一个 urlpatterns 元组，里面包含了路径名和函数名；在 函数 application 中遍历 urlpatterns 元组，路径存在则返回函数名，不存在则返回 404

from wsgiref.simple_server import make_server

def routers():
    urlpatterns = (
        ('/book', f1),
        ('/web', f2),
    )
    return  urlpatterns

def f1(x):
    return [b'<h1>Hello, book</h1>']

def f2(x):
    return [b'<h1>Hello, web</h1>']

def application(environ, start_response):
    start_response('200 OK', [('Content-Type', 'text/html')])

    urlpatterns = routers()
    path = environ["PATH_INFO"]
    func = None
    for item in urlpatterns:
        if item[0] == path:
            func = item[1]
            break
    if func:
        return func(environ)
    else:
        return ["<h1>404</h1>".encode("utf8")]

httpd = make_server('', 8888, application)

print('Serving HTTP on port 8888...')
httpd.serve_forever()