The 6th Zhejiang Provincial Collegiate Programming Contest->ProblemK:K-Nice
http://acm.zju.edu.cn/onlinejudge/showProblem.do?problemCode=3212
题意:构造出一个n*m的有k个上下左右的和等于中间数的小矩阵的任意矩阵。
就是输出k个全是0的矩阵(符合条件),然后其他的矩阵用数字填掉
#include<bits/stdc++.h>
using namespace std;
int main()
{
int T, n, m, k, i, j;
scanf("%d", &T);
while(T--) {
scanf("%d%d%d", &n, &m, &k);
k = (n-)*(m-) - k;//不符合条件的矩阵
for(i = ; i <= n; i++) {
printf("");
for(j = ; j <= m-; j++) {
if(k>)
printf(" %d", k--);
else
printf("");
}
printf(" 0\n");
}
}
return ;
}
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