每天一道LeetCode--434. Number of Segments in a String
Count the number of segments in a string, where a segment is defined to be a contiguous sequence of non-space characters.
For example,
Input: "Hello, my name is John"
Output: 5
public int countSegments(String s) {
String trimmed = s.trim();
if (trimmed.length() == 0)
return 0;
else
return trimmed.split("\\s+").length;
}
每天一道LeetCode--434. Number of Segments in a String的更多相关文章
- 434. Number of Segments in a String
原题: 434. Number of Segments in a String 解题: 刚看到题目时,觉得可以通过统计空格个数,但想想有可能会有多个空格的情况 思路: 一:遍历字符,if条件碰到非空格 ...
- 【LeetCode】434. Number of Segments in a String 解题报告(Python)
作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 统计 正则表达式 字符串分割 日期 题目地址:htt ...
- 【LeetCode】434. Number of Segments in a String
Count the number of segments in a string, where a segment is defined to be a contiguous sequence of ...
- [LeetCode] 434. Number of Segments in a String_Easy
Count the number of segments in a string, where a segment is defined to be a contiguous sequence of ...
- 434. Number of Segments in a String 字符串中的单词个数
[抄题]: Count the number of segments in a string, where a segment is defined to be a contiguous sequen ...
- [LC] 434. Number of Segments in a String
Count the number of segments in a string, where a segment is defined to be a contiguous sequence of ...
- 434 Number of Segments in a String 字符串中的单词数
统计字符串中的单词个数,这里的单词指的是连续的非空字符.请注意,你可以假定字符串里不包括任何不可打印的字符.示例:输入: "Hello, my name is John"输出: 5 ...
- LeetCode_434. Number of Segments in a String
434. Number of Segments in a String Easy Count the number of segments in a string, where a segment i ...
- [LeetCode] Number of Segments in a String 字符串中的分段数量
Count the number of segments in a string, where a segment is defined to be a contiguous sequence of ...
- Leetcode: Number of Segments in a String
Count the number of segments in a string, where a segment is defined to be a contiguous sequence of ...
随机推荐
- Codeforces Round #221 (Div. 1) B. Maximum Submatrix 2 dp排序
B. Maximum Submatrix 2 Time Limit: 20 Sec Memory Limit: 256 MB 题目连接 http://codeforces.com/problemset ...
- Codeforces Beta Round #4 (Div. 2 Only) C. Registration system hash
C. Registration system Time Limit: 20 Sec Memory Limit: 256 MB 题目连接 http://codeforces.com/problemset ...
- 安卓高手之路之PackageManagerservice
源码位置:frameworks/base/core/java/android/content/pm/PackageParser.java 源文件路径:android\frameworks\base\s ...
- Android progressBar 自定义圆形旋转图片
项目需要中需要更换progressbar的旋转背景,在网上找了几种办法,但是都有各自的问题 于是结合网上所讲,研究了一下终于ok了: 一 首相在drawable文件夹中建立如下旋转动画文件 <? ...
- centos 安装git server
1.yum install lrzsz wget git 2.安装gitosis:gitosis为Git用户权限管理系统,通过管理服务端的/home/git/.ssh/authorized_key文件 ...
- 剑指 offer set 2 从头到尾打印链表
总结 1. 书中给出的最终解法是递归或用堆栈模拟递归. 之前我一直不清楚是否还有更优雅的做法, 看样是没了
- systemtap-与 oracle 转
https://baoz.net/using-systemtap/ http://nanxiao.me/category/%E6%8A%80%E6%9C%AF/systemtap-%E7%AC%94% ...
- 关于composer
Composer PHP依赖管理的新时代http://segmentfault.com/a/1190000000353129 Composer 的主页 https://getcomposer.or ...
- 重置kafka的offset
如果你在使用Kafka来分发消息,在数据处理的过程中可能会出现处理程序出异常或者是其它的错误,会造成数据丢失或不一致.这个时候你也许会想要通过kafka把数据从新处理一遍,我们知道kafka默认会在磁 ...
- html 文件上传框 input标签
文件上传框 有时候,需要用户上传自己的文件,文件上传框看上去和其它 文本域差不多,只是它还包含了一个浏览按钮.访问者可以通 过输入需要上传的文件的路径或者点击浏览按钮选择需要上传 的文件. 代码格式: ...