【LeetCode 33】Search in Rotated Sorted Array
Search in Rotated Sorted Array
分段有序的数组,二分查找返回下标,没有返回-1
数组有序之后经过 rotated, 比如:6 1 2 3 4 5 or 5 6 7 8 1 2
思路是:
(1)nums[m] == target return m
(2)必定有一段是有序的,找到有序段:
// m to r is ordered
if(nums[m] < nums[r]){
if nums[m] <= targe <= nums[r] , then l = m + 1;
else: r = m - 1
// l to m is ordered
else
if nums[l] <= targe <= nums[m] , then r = m - 1
else left = m + 1;
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