76. Minimum Window Substring *HARD*
Given a string S and a string T, find the minimum window in S which will contain all the characters in T in complexity O(n).
For example,
S = "ADOBECODEBANC"
T = "ABC"
Minimum window is "BANC"
.
Note:
If there is no such window in S that covers all characters in T, return the empty string ""
.
If there are multiple such windows, you are guaranteed that there will always be only one unique minimum window in S.
76. Minimum Window Substring *HARD*的更多相关文章
- 刷题76. Minimum Window Substring
一.题目说明 题目76. Minimum Window Substring,求字符串S中最小连续字符串,包括字符串T中的所有字符,复杂度要求是O(n).难度是Hard! 二.我的解答 先说我的思路: ...
- 【LeetCode】76. Minimum Window Substring
Minimum Window Substring Given a string S and a string T, find the minimum window in S which will co ...
- [LeetCode] 76. Minimum Window Substring 最小窗口子串
Given a string S and a string T, find the minimum window in S which will contain all the characters ...
- 76. Minimum Window Substring
题目: Given a string S and a string T, find the minimum window in S which will contain all the charact ...
- [LeetCode] 76. Minimum Window Substring 解题思路
Given a string S and a string T, find the minimum window in S which will contain all the characters ...
- [leetcode]76. Minimum Window Substring最小字符串窗口
Given a string S and a string T, find the minimum window in S which will contain all the characters ...
- 76. Minimum Window Substring(hard 双指针)
Given a string S and a string T, find the minimum window in S which will contain all the characters ...
- 76. Minimum Window Substring (JAVA)
Given a string S and a string T, find the minimum window in S which will contain all the characters ...
- [LC] 76. Minimum Window Substring
Given a string S and a string T, find the minimum window in S which will contain all the characters ...
- 【一天一道LeetCode】#76. Minimum Window Substring
一天一道LeetCode 本系列文章已全部上传至我的github,地址:ZeeCoder's Github 欢迎大家关注我的新浪微博,我的新浪微博 欢迎转载,转载请注明出处 (一)题目 Given a ...
随机推荐
- 20165211 2017-2018-2 《Java程序设计》第6周学习总结
20165211 2017-2018-2 <Java程序设计>第6周学习总结 教材学习内容总结 本周,我学习了书本上第八.十五两章的内容,以下是我整理的主要知识. 第八章 常用实用类 St ...
- linux内核分析 第六周
一.进程的描述 为了管理进程,内核必须对每个进程进行清晰的描述,进程描述符提供了内核所需了解的进程信息. 1.进程控制块PCB--task_struct 进程状态 进程打开的文件 进程优先级信息 2. ...
- SQL数据插入字符串时转义函数
函数一: std::string CheckString(std::string& strSource) { std::string strOldValue = "'"; ...
- C#对象的new和不new的区别
new:为对象分配空间. 首先,直接声明一个变量:byte[] test;只是有了一个变量名字,而它是没有实际空间的,需要分配空间: 分配空间的方法: 1.使用new,byte[] test = ne ...
- Python3基础 str 循环输出list中每个单词及其长度
Python : 3.7.0 OS : Ubuntu 18.04.1 LTS IDE : PyCharm 2018.2.4 Conda ...
- UNIX网络编程--简介(一)【转】
本文转载自:http://blog.csdn.net/yusiguyuan/article/details/11760187 一.概述 a) 在编写与计算机通信的程序时,首先要确定的就是和计算机通信的 ...
- bootstrap的carousel图片轮播
整个轮播是放在一个div .carousel和.slide的div中的, 包括3个部分: 1. 第一个部分indicator位于下方的指示器部分. 结构是一个ol和li, ol的类是carousel- ...
- luogu P4396 [AHOI2013]作业
目录 题目 思路 错误&&傻叉 代码 题目 luogu 思路 每次都是插入比之前所有数字大的数,所以之前的答案就不会改变 用fhq-treap求出原序列,然后用树状数组依次算出每个值得 ...
- ubuntu 把软件源修改为国内源和更新
1. 备份原始文件 sudo cp /etc/apt/sources.list /etc/apt/sources.list.backup 2. 修改文件并添加国内源 vi /etc/apt/sourc ...
- 基础dp 记录
51nod 1134 最长递增子序列 #include<iostream> #include<cstdio> #include<cstring> #include& ...