Luogu [USACO08OPEN]寻宝之路Clear And Present Danger
题目描述
Farmer John is on a boat seeking fabled treasure on one of the N (1 <= N <= 100) islands conveniently labeled 1..N in the Cowribbean Sea.
The treasure map tells him that he must travel through a certain sequence A_1, A_2, ..., A_M of M (2 <= M <= 10,000) islands, starting on island 1 and ending on island N before the treasure will appear to him. He can visit these and other islands out of order and even more than once, but his trip must include the A_i sequence in the order specified by the map.
FJ wants to avoid pirates and knows the pirate-danger rating (0 <= danger <= 100,000) between each pair of islands. The total danger rating of his mission is the sum of the danger ratings of all the paths he traverses.
Help Farmer John find the least dangerous route to the treasure that satisfies the treasure map's requirement.
农夫约翰正驾驶一条小艇在牛勒比海上航行.
海上有N(1≤N≤100)个岛屿,用1到N编号.约翰从1号小岛出发,最后到达N号小岛.
一张藏宝图上说,如果他的路程上经过的小岛依次出现了Ai,A2,…,AM(2≤M≤10000)这样的序列(不一定相邻),那他最终就能找到古老的宝藏. 但是,由于牛勒比海有海盗出没.约翰知道任意两个岛屿之间的航线上海盗出没的概率,他用一个危险指数Dij(0≤Dij≤100000)来描述.他希望他的寻宝活动经过的航线危险指数之和最小.那么,在找到宝藏的前提下,这个最小的危险指数是多少呢?
输入输出格式
输入格式:
Line 1: Two space-separated integers: N and M
Lines 2..M+1: Line i+1 describes the i_th island FJ must visit with a single integer: A_i
- Lines M+2..N+M+1: Line i+M+1 contains N space-separated integers that are the respective danger rating of the path between island i and islands 1, 2, ..., and N, respectively. The ith integer is always zero.
输出格式:
- Line 1: The minimum danger that Farmer John can encounter while obtaining the treasure.
输入输出样例
3 4
1
2
1
3
0 5 1
5 0 2
1 2 0
7
说明
There are 3 islands and the treasure map requires Farmer John to visit a sequence of 4 islands in order: island 1, island 2, island 1 again, and finally island 3. The danger ratings of the paths are given: the paths (1, 2); (2, 3); (3, 1) and the reverse paths have danger ratings of 5, 2, and 1, respectively.
He can get the treasure with a total danger of 7 by traveling in the sequence of islands 1, 3, 2, 3, 1, and 3. The cow map's requirement (1, 2, 1, and 3) is satisfied by this route. We avoid the path between islands 1 and 2 because it has a large danger rating.
Luogu [USACO08OPEN]寻宝之路Clear And Present Danger的更多相关文章
- 洛谷——P2910 [USACO08OPEN]寻宝之路Clear And Present Danger
P2910 [USACO08OPEN]寻宝之路Clear And Present Danger 题目描述 Farmer John is on a boat seeking fabled treasur ...
- P2910 [USACO08OPEN]寻宝之路Clear And Present Danger 洛谷
https://www.luogu.org/problem/show?pid=2910 题目描述 Farmer John is on a boat seeking fabled treasure on ...
- (最短路 Floyd) P2910 [USACO08OPEN]寻宝之路Clear And Present Danger 洛谷
题意翻译 题目描述 农夫约翰正驾驶一条小艇在牛勒比海上航行. 海上有N(1≤N≤100)个岛屿,用1到N编号.约翰从1号小岛出发,最后到达N号小岛. 一张藏宝图上说,如果他的路程上经过的小岛依次出现了 ...
- 洛谷 P2910 [USACO08OPEN]寻宝之路Clear And Present Danger
题目描述 Farmer John is on a boat seeking fabled treasure on one of the N (1 <= N <= 100) islands ...
- P2910 [USACO08OPEN]寻宝之路Clear And Present Danger |Floyd
题目描述 农夫约翰正驾驶一条小艇在牛勒比海上航行. 海上有N(1≤N≤100)个岛屿,用1到N编号.约翰从1号小岛出发,最后到达N号小岛. 一张藏宝图上说,如果他的路程上经过的小岛依次出现了Ai,A2 ...
- [USACO08OPEN]寻宝之路Clear And Present Danger
OJ题号:洛谷2910 思路:Floyd #include<cstdio> #include<algorithm> using namespace std; int main( ...
- 题解 P2910 【[USACO08OPEN]寻宝之路Clear And Present Danger】
说起来这还是本蒟蒻学完Floyd之后做的第一道题. emm...这是一道裸题,题目大致是说有一堆岛,岛之间有海盗,因此每一条边都有一个危险指数(权重),然后给出一段必须经过的路线,求从一号小岛走到N号 ...
- Bzoj 1624: [Usaco2008 Open] Clear And Present Danger 寻宝之路 最短路,floyd
1624: [Usaco2008 Open] Clear And Present Danger 寻宝之路 Time Limit: 5 Sec Memory Limit: 64 MBSubmit: 5 ...
- BZOJ 1624: [Usaco2008 Open] Clear And Present Danger 寻宝之路( 最短路 )
直接floyd.. ----------------------------------------------------------------------- #include<cstdio ...
随机推荐
- mysql 查询缓存配置和查看
Mysql 查询缓存 查询缓存的作用就是当查询接收到一个和之前同样的查询,服务器将会从查询缓存种检索结果,而不是再次分析和执行上次的查询.这样就大大提高了性能,节省时间. 1.配置查询缓存 修改配置文 ...
- 【LeetCode】118. Pascal's Triangle
题目: Given numRows, generate the first numRows of Pascal's triangle. For example, given numRows = 5,R ...
- 【WPF】在新线程上打开窗口
当WPF应用程序运行时,默认会创建一个UI主线程(因为至少需要一个),并在该UI线程上启动消息循环.直到消息循环结束,应用程序就随即退出.那么,问题就来了,能不能创建新线程,然后在新线程上打开一个新窗 ...
- touchmover手机移动端的拖动
<!DOCTYPE html><html> <head> <meta charset="utf-8"> <meta name= ...
- I/O多路复用之epoll实战
概念 IO多路复用是指内核一旦发现进程指定的一个或者多个IO条件准备读取,它就通知该进程 通俗理解(摘自网上一大神) 这些名词比较绕口,理解涵义就好.一个epoll场景:一个酒吧服务员(一个线程),前 ...
- VB6之扫雷克星
很久之前,那时候我还不太会玩(现在也不厉害)扫雷这个游戏,同学总在我面前炫耀自己的技术有多叼.“高级,99颗雷,只需三分钟...”,如此这般.也许确实需要天赋,我总要排查个半天才敢点下左键,然后就BO ...
- Newtonsoft.Json输出JSON 时动态忽略属性
一,前言 最近做项目采用Json形式和其他客户端交互,借助于Newtonsoft.Json . 由于业务场景不同,输出的Json内容也不同.要想忽略的属性,可以借助Newtonsoft.Json的特性 ...
- [UWP]浅谈按钮设计
一时兴起想谈谈UWP按钮的设计. 按钮是UI中最重要的元素之一,可能也是用得最多的交互元素.好的按钮设计可以有效提高用户体验,构造让人眼前一亮的UI.而且按钮通常不会影响布局,小小的按钮无论怎么改也不 ...
- Js中的数据属性和访问器属性
Js中的数据属性和访问器属性 在javaScript中,对象的属性分为两种类型:数据属性和访问器属性. 一.数据属性 1.数据属性:它包含的是一个数据值的位置,在这可以对数据值进行读写. 2.数据属性 ...
- 【故障处理】ERROR 1872 (HY000): Slave failed to initialize relay log info structure from the repository
今天在使用冷备份文件重做从库时遇到一个报错,值得研究一下. 版本:MySQL5.6.27 一.报错现象 dba:(none)> start slave; ERROR (HY000): Slave ...