(栈)leetcode 946. Validate Stack Sequences
Given two sequences pushed
and popped
with distinct values, return true
if and only if this could have been the result of a sequence of push and pop operations on an initially empty stack.
Example 1:
- Input: pushed = [1,2,3,4,5], popped = [4,5,3,2,1]
- Output: true
- Explanation: We might do the following sequence:
- push(1), push(2), push(3), push(4), pop() -> 4,
- push(5), pop() -> 5, pop() -> 3, pop() -> 2, pop() -> 1
Example 2:
- Input: pushed = [1,2,3,4,5], popped = [4,3,5,1,2]
- Output: false
- Explanation: 1 cannot be popped before 2.
Note:
0 <= pushed.length == popped.length <= 1000
0 <= pushed[i], popped[i] < 1000
pushed
is a permutation ofpopped
.pushed
andpopped
have distinct values.
栈
C++代码:
- class Solution {
- public:
- bool validateStackSequences(vector<int>& pushed, vector<int>& popped) {
- stack<int> s;
- int len = pushed.size();
- int j = ;
- for(int n : pushed){
- s.push(n);
- while(!s.empty() && j < len && s.top() == popped[j]){
- s.pop();
- j++;
- }
- }
- return j == len;
- }
- };
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