Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists.

Example:

Input: 1->2->4, 1->3->4
Output: 1->1->2->3->4->4

Solution 1:

var mergeTwoLists = function(l1, l2) {
if (!l1 && !l2) {
return null;
} if (!l1 && l2) {
return l2;
} if (!l2 && l1) {
return l1;
} const smallerNode = l1.val <= l2.val ? l1 : l2;
if (smallerNode.val === l1.val) {
smallerNode.next = mergeTwoLists(l1.next, l2);
} else {
smallerNode.next = mergeTwoLists(l1, l2.next);
} return smallerNode;
}

Solution 2: Better

/**
* Definition for singly-linked list.
* function ListNode(val) {
* this.val = val;
* this.next = null;
* }
*/
/**
* @param {ListNode} l1
* @param {ListNode} l2
* @return {ListNode}
*/
var mergeTwoLists = function(l1, l2) { let curr = temp = new ListNode(0) while (l1 && l2) {
if (l1.val < l2.val) {
curr.next = l1;
l1 = l1.next;
} else {
curr.next = l2;
l2 = l2.next;
}
curr = curr.next;
} if (l1) {
curr.next = l1;
} if (l2) {
curr.next = l2;
} return temp.next;
};

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