620. Not Boring Movies
X city opened a new cinema, many people would like to go to this cinema. The cinema also gives out a poster indicating the movies’ ratings and descriptions.
Please write a SQL query to output movies with an odd numbered ID and a description that is not 'boring'. Order the result by rating.
For example, table cinema:
+---------+-----------+--------------+-----------+
| id | movie | description | rating |
+---------+-----------+--------------+-----------+
| 1 | War | great 3D | 8.9 |
| 2 | Science | fiction | 8.5 |
| 3 | irish | boring | 6.2 |
| 4 | Ice song | Fantacy | 8.6 |
| 5 | House card| Interesting| 9.1 |
+---------+-----------+--------------+-----------+
For the example above, the output should be:
+---------+-----------+--------------+-----------+
| id | movie | description | rating |
+---------+-----------+--------------+-----------+
| 5 | House card| Interesting| 9.1 |
| 1 | War | great 3D | 8.9 |
+---------+-----------+--------------+-----------+ 查询出id为奇数,description不是boring,按rating降序的 MySQL(159ms):
# Write your MySQL query statement below
SELECT id , movie , description , rating
FROM cinema
WHERE id&1 AND description != 'boring'
ORDER BY rating DESC ;
620. Not Boring Movies的更多相关文章
- LeetCode - 620. Not Boring Movies
X city opened a new cinema, many people would like to go to this cinema. The cinema also gives out a ...
- LeetCode: 620 Not Boring Movies(easy)
题目: X city opened a new cinema, many people would like to go to this cinema. The cinema also gives o ...
- leetcode 620. Not Boring Movies 用where语句判断
https://leetcode.com/problems/not-boring-movies/description/ 不管题目简不简单,现在先熟悉语法. 直接用where语句判断即可,判断奇偶可以 ...
- LeetCode 620. Not Boring Movies (有趣的电影)
题目标签: 题目给了我们一个 cinema 表格, 让我们找出 不无聊的电影,并且id 是奇数的,降序排列. 比较直接简单的,具体看code. Java Solution: Runtime: 149 ...
- [Swift]LeetCode620. 有趣的电影 | Not Boring Movies
SQL架构 Create table If Not Exists cinema (id ), description varchar(), rating , )) Truncate table cin ...
- [LeetCode] 620. Not Boring Movies_Easy tag: SQL
X city opened a new cinema, many people would like to go to this cinema. The cinema also gives out a ...
- All LeetCode Questions List 题目汇总
All LeetCode Questions List(Part of Answers, still updating) 题目汇总及部分答案(持续更新中) Leetcode problems clas ...
- Leetcode中的SQL题目练习(一)
595. Big Countries https://leetcode.com/problems/big-countries/description/ Description name contine ...
- 【sql】leetcode习题 (共 42 题)
[175]Combine Two Tables (2018年11月23日,开始集中review基础) Table: Person +-------------+---------+ | Column ...
随机推荐
- sublime Text 块编辑方法
比如我们要把SQL语句中的多表查询结果封装成pojo SQL: SELECT a.id, a.title, a.sell_point, a.price, a.image, b.`name` categ ...
- Picture POJ - 1177 (线段树-扫描线)
A number of rectangular posters, photographs and other pictures of the same shape are pasted on a wa ...
- HDU3579 线性同余方程(模板 余数不一定互质)
Hello Kiki Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others) Total Su ...
- [freemarker篇]03.如何处理空值
我想说的一点,我写的东西没有那么权威,这都是我实际开发中使用的,可能缺少很多! 例如这篇要说的如何处理空值,我发现我使用的跟网上很多写的不太一样,我也没有过多的去尝试网上的那么多写法! 抱歉,我只是写 ...
- [LeetCode] 1. Two Sum ☆
Given an array of integers, return indices of the two numbers such that they add up to a specific ta ...
- android之解析json数据格式详解
1.JSON解析 (1).解析Object之一: view sourceprint? 1 {"url":"http://www.cnblogs.com/qianx ...
- ZooKeeper概述(三)
ZooKeeper:分布式应用的分布协调服务 ZooKeeper是一个为分布式应用提供的分布的开源的协调服务.它暴露一组简单的原子操作,分布式系统可以在这之上为同步,配置管理,和组和命名实现更高级的服 ...
- Item 30 用enum代替int常量类型枚举,string常量类型枚举
1.用枚举类型替代int枚举类型和string枚举类型 public class Show { // Int枚举类型 // public static final int APPLE_FUJI ...
- 【51NOD-0】1046 A^B Mod C
[算法]快速幂运算 [题解]快速幂的原理是把幂用二进制表示,从最低位a,次低位a2,次次低位(a2)2. #include<cstdio> long long quick_pow(long ...
- SCU 1029 Humble Numbers (打表处理)
题目链接 题意:素因子中只有2 3 5 7的数称为谦逊的数,1也是谦逊的数,题目中已经给出了前20个谦逊的数.给定数字n,按格式输出第n个谦逊的数. 题解:打表即可,注意打表的技巧就行了. ps:这道 ...