1、题目描述

2、问题分析

从每一个num[i]往前扫描即可。

3、代码

 int findLengthOfLCIS(vector<int>& nums) {
if( nums.size() <= ){
return nums.size() ;
} vector<int> dp(nums.size(), );
int maxans = ; for(int i = ; i < nums.size() ; i++){
int maxI = ;
for( int j = i-; j >= ; j--){
if( nums[j] < nums[j+] )
maxI++;
else
break;
} maxans = max( maxI, maxans);
}
return maxans; }

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