Codeforces Gym 100571A A. Cursed Query 离线

A. Cursed Query
Time Limit: 20 Sec

Memory Limit: 256 MB

题目连接

http://codeforces.com/gym/100571/problem/A

Description

De Prezer loves movies and series. He has watched the Troy for like 100 times and also he is a big fan of Supernatural series.So, he did some researches and found a cursed object which had n lights on it and initially all of them were turned off.Because of his love to theTroy, he called that object Troy.

He looked and saw a note on it in Khikulish (language of people of Khikuland): "Ma in hame rah umadim, hala migi ... ? ... Mage man De Prezer am k mikhay mano ... ? .... Man se sale ... To boro .... beshur manam miram ... o mishuram".

He doesn't know Khikulish, so just ignored the note and tested the Troy.

He realized that the light number i stays turned on for exactly ai seconds, and then it turns itself off (if it is turned on, in time t, in timet + ai - 1 it will be turned on, but on time t + ai it won't be) and the next light will be turned on (if i < n, next light is the light number i + 1, otherwise it is light with number 1).

For example if n = 2 and we turn on the first light in time 0, it will be turned on in hole interval [0, a1) and in hole interval [a1, a1 + a2)the second light will be turned on and so on.

In time 0 he turns on the light number 1.

De Prezer also loves query.So he gives you q queries.In each query he will give you integer t (the time a revengeful ghost attacked him) and you should print the number of the light that is turned on, in time t.

Input

The first line of input contains two integers n and q.

The second line contains n space separated integers, a1, a2, ..., an .

The next q lines, each line contains a single integer t .

1 ≤ n, q ≤ 105

1 ≤ ai ≤ 109

1 ≤ t ≤ 1018

Output

For each query, print the answer in one line.

Sample Input

5 7
1 2 3 4 5
1
2
3
7
14
15
16

Sample Output

2
2
3
4
5
1
2

HINT

题意

给你一些灯，第一个灯会在[0,a1)的时候亮，第二栈灯会在[a1,a1+a2)的时候亮，然后哒哒哒，循环

有Q个询问，问你在t秒时，是哪栈灯在亮

题解：

我是离线做的，但是感觉二分也可以

代码

#include <cstdio>
#include <cmath>
#include <cstring>
#include <ctime>
#include <iostream>
#include <algorithm>
#include <set>
#include <vector>
#include <sstream>
#include <queue>
#include <typeinfo>
#include <fstream>
#include <map>
#include <stack>
typedef long long ll;
using namespace std;
//freopen("D.in","r",stdin);
//freopen("D.out","w",stdout);
#define sspeed ios_base::sync_with_stdio(0);cin.tie(0)
#define test freopen("test.txt","r",stdin)
const int maxn=;
#define mod 1000000007
#define eps 1e-9
const int inf=0x3f3f3f3f;
const ll infll = 0x3f3f3f3f3f3f3f3fLL;
inline ll read()
{
    ll x=,f=;char ch=getchar();
    while(ch<''||ch>''){if(ch=='-')f=-;ch=getchar();}
    while(ch>=''&&ch<=''){x=x*+ch-'';ch=getchar();}
    return x*f;
}
//*************************************************************************************

ll a[maxn];
ll sum[maxn];
struct node
{
    ll x,y,z;
};
node query[maxn];
bool cmp(node a,node b)
{
    return a.x<b.x;
}
bool cmp1(node a,node b)
{
    return a.y<b.y;
}
int main()
{
    ll n,q;
    n=read(),q=read();
    for(int i=;i<=n;i++)
        a[i]=read();
    for(int i=;i<=n;i++)
        sum[i]+=a[i]+sum[i-];
    for(int i=;i<=q;i++)
    {
        query[i].x=read();
        query[i].x%=sum[n];
        query[i].y=i;
    }
    sort(query+,query++q,cmp);
    int j=;
    for(int i=;i<=q;i++)
    {
        while(sum[j]<=query[i].x&&j<n)
            j++;
        query[i].z=j;
    }
    sort(query+,query++q,cmp1);
    for(int i=;i<=q;i++)
        printf("%d\n",query[i].z);
}