G a+b+c+d=?

G

a+b+c+d=?

链接：https://ac.nowcoder.com/acm/contest/338/G
来源：牛客网

题目描述

This is a very simple problem! Your only job is to calculate a + b + c + d!

输入描述:

There are several cases.

In the first line, there is a single integer T.(T <= 200)

In the next T lines, each line contains four integers a, b, c and d(-2^61 <= a,b,c,d <=2^61)

输出描述:

output T lines.

Each line output one integer represent the answer of a + b + c + d

示例1

输入

复制

1
1 2 3 4

输出

复制

10

double || long double 都可以

#include<stdio.h>
int main()
{
    int t;
    scanf("%d",&t);
    while(t--)
    {
        long double a,b,c,d;
        scanf("%LF%LF%LF%LF",&a,&b,&c,&d);
        long double sum = 0;
        sum = a+b+c+d;
        printf("%.0LF\n",sum);
    }
}

py过的

n=int(input())
for i in range(n):
        a,b,c,d = map(int,input().split())
        print(a+b+c+d)
    

• 题解:这是一道很简单的题目，主要考察对于长整型数据范围的认 知，直接加法是会出现错误的，需要在a,b,c,d都等于2^61时特判 直接输出2^,其他情况直接输出结果即可！