题意:

输入一个正整数N(<=1e5),代表出口的数量,接下来输入N个正整数表示当前出口到下一个出口的距离。接着输入一个正整数M(<=10000),代表询问的次数,每次询问输入两个出口的序号,输出他们之间的最小距离。

AAAAAccepted code:

 #define HAVE_STRUCT_TIMESPEC
#include<bits/stdc++.h>
using namespace std;
int dis[],sum[];
int main(){
ios::sync_with_stdio(false);
cin.tie(NULL);
cout.tie(NULL);
int n;
cin>>n;
for(int i=;i<=n;++i){
cin>>dis[i];
sum[i]=sum[i-]+dis[i];
}
int q;
cin>>q;
for(int i=;i<=q;++i){
int u,v;
cin>>u>>v;
if(v<u)
swap(u,v);
int x=sum[v-]-sum[u-];
int y=sum[n]-x;
cout<<min(x,y)<<"\n";
}
return ;
}

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