pid=5323" target="_blank" style="">链接

Solve this interesting problem

Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)

Total Submission(s): 511    Accepted Submission(s): 114

Problem Description
Have you learned something about segment tree? If not, don’t worry, I will explain it for you.

Segment Tree is a kind of binary tree, it can be defined as this:

- For each node u in Segment Tree, u has two values: Lu and Ru.

- If Lu=Ru,
u is a leaf node. 

- If Lu≠Ru,
u has two children x and y,with Lx=Lu,Rx=⌊Lu+Ru2⌋,Ly=⌊Lu+Ru2⌋+1,Ry=Ru.

Here is an example of segment tree to do range query of sum.








Given two integers L and R, Your task is to find the minimum non-negative n satisfy that: A Segment Tree with root node's value Lroot=0 and Rroot=ncontains
a node u with Lu=L and Ru=R.
 
Input
The input consists of several test cases. 

Each test case contains two integers L and R, as described above.

0≤L≤R≤109

LR−L+1≤2015
 
Output
For each test, output one line contains one integer. If there is no such n, just output -1.
 
Sample Input
6 7
10 13
10 11
 
Sample Output
7
-1
12
 
Source
 

题意:
给定区间[l,r]
用线段树的递归建树方式build(1, n)
问最小的n是多少,使得build(1,n) 中能直接建出区间[l,r]
思路:
注意一下范围,然后推算一下就能发现这个区间距离根节点的距离不超过10
所以从底向上搜就好了

代码

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