https://pintia.cn/problem-sets/994805342720868352/problems/994805422639136768

Behind the scenes in the computer's memory, color is always talked about as a series of 24 bits of information for each pixel. In an image, the color with the largest proportional area is called the dominant color. A strictly dominant color takes more than half of the total area. Now given an image of resolution M by N (for example, 800x600), you are supposed to point out the strictly dominant color.

Input Specification:

Each input file contains one test case. For each case, the first line contains 2 positive numbers: M (<=800) and N (<=600) which are the resolutions of the image. Then N lines follow, each contains M digital colors in the range [0, 2^24^). It is guaranteed that the strictly dominant color exists for each input image. All the numbers in a line are separated by a space.

Output Specification:

For each test case, simply print the dominant color in a line.

Sample Input:

5 3
0 0 255 16777215 24
24 24 0 0 24
24 0 24 24 24

Sample Output:

24

代码:
#include <bits/stdc++.h>
using namespace std; int a[801][801];
map<int, int> mp; int main() {
int n, m;
scanf("%d%d", &m, &n);
for(int i = 1; i <= n; i ++) {
for(int j = 1; j <= m; j ++) {
scanf("%d", &a[i][j]);
mp[a[i][j]] ++;
}
} int zlr;
int cnt = 0;
for(int i = 1; i <= n; i ++) {
for(int j = 1; j <= m; j ++) {
if(mp[a[i][j]] > cnt) {
cnt = mp[a[i][j]];
zlr = a[i][j];
}
}
}
printf("%d\n", zlr); return 0;
}

  

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