Codeforces Gym 100286I iSharp 模拟

原题地址：http://codeforces.com/gym/100286/attachments/download/2013/20082009-acmicpc-northeastern-european-regional-contest-neerc-08-en.pdf

题意大概就是让你把写在一块的变量分开。。水题，用string过。

详见代码：

//#include<iostream>
#include<fstream>
#include<string>
#include<algorithm>
using namespace std;

string s;
string allType;
string va,ty;
string Analyze(string v) {
    int t = ;
    while ((v[t] >= 'A' && v[t] <= 'Z') || (v[t] >= 'a' && v[t] <= 'z'))t++;
    va.assign(v.begin(), v.begin() + t);
    ty.assign(v.begin() + t, v.end());
    reverse(ty.begin(), ty.end());
    return ty + " " + va + ";";
}

string a;

int main() {
    ifstream cin("isharp.in");
    ofstream cout("isharp.out");
    cin.sync_with_stdio(false);
    getline(cin, s);
    int tmp = ;
    while (s[tmp] != ' ')tmp++;
    allType.assign(s.begin(), s.begin() + tmp);
    tmp++;
    while (true) {
        int t = tmp;
        while (s[t] != ',' && s[t] != ';')t++;
        a.assign(s.begin() + tmp, s.begin() + t);
        a = allType + Analyze(a);

        int c = ;
        for (int i = ; i < a.length(); i++) {
            if (a[i] == '[' || a[i] == ']') {
                c++;
                if (c % )cout << '[';
                else cout << ']';
            }
            else cout << a[i];
        }
        cout << endl;
        if (s[t] == ';')break;
        tmp = t + ;
    }
    return ;
}